Ask question

Ask question

All categories

4 years ago

10

PLEASE HELP Use the rules of exponents to simplify the expressions. Place a final answer in fraction form. (-1/2)to the power of

3 *(-1/2) to the power of 2

1 answer:

Len [333]4 years ago

5 0

Answer:

-1/32.

Step-by-step explanation:

(-1/2)^3 * (-1/2)^2

= -1/8 * 1/4

= -1/32.

You might be interested in

A single ticket to the magic show costs ttt dollars, but there is a discount of 5\%5%5, percent per ticket if a group buys 10101

valentina_108 [34]

Answer: 10 t -0.5 t is the total cost of the ticket for the group of 10 people after getting discount.

Where 10 t is the initial cost of ticket without discount and 0.5 t is the total discount.

Step-by-step explanation:

Here, t represents the cost of one ticket.

Therefore, For 10 person the cost of the ticket = 10 t

And, According to the question, there is a discount of 5% percent per ticket if a group buys 10 tickets.

Thus, the discount for the group of ten people = 5% of 10 t = 0.5 t

The the total cost for the group of ten people after getting the discount = 10 t - 0.5 t

6 0

3 years ago

Read 2 more answers

Look at the picture please hell

ohaa [14]

Answer:

2 one that's the right one

7 0

3 years ago

During a promotional weekend, a clothing store gives a $50 gift card to every 75th person who enters the store. On Sunday, there

jeka57 [31]

<h2>Hello!</h2>

The answer is: 34 persons received the $50 gift card.

<h2>Why?</h2>

If we need to know how many many people received a $50 gift card over the two days (Sunday and Monday) we need to divide the total attendance by the number 75 because every 75 persons, there is a $50 gift card.

So, calculating we have:

$TotalAttendance=SundayAttendance+MondayAttendance\\TotalAttendance=1030+1562=2592$

Then, dividing the total attendance by 75 to know how many people received a $50 gift card over the two days, we have:

$ReceivedGiftCards=\frac{2592}{75}=34.6$

Hence, rounding to the nearest whole number, 34 persons received the $50 gift card.

Have a nice day!

4 0

3 years ago

Radda [10]

Answer/Step-by-step explanation:

Given :

The linear functions f(x) and g(x) are represented on the graph, where g(x) is a transformation of f(x):

To Find: two types of transformations that can be used to transform f(x) to g(x).

=================================================================

Part A: Describe two types of transformations that can be used to transform f(x) to g(x). (2 points)

Solution Part A:

f(x) = x/5 + y/(-10) = 1

=> 2x - y = 10

=================================================================

Part B: Solve for k in each type of transformation. (4 points)

Solution Part B:

g(x) = x/(-3) + y/6 = 1

=> 2x - y = - 6

=================================================================

an equation for each type of transformation that can be used to transform f(x) to g(x). (4 points)

Solution Part C:

Transformations :

g(x) = f(x) + 16

g(x) = f(x + 8)

4 0

3 years ago

Determine whether each point lies on the graph of the equation.(a) 2x - y - 3 = 0 (a) (1, 2)Yes, the point is on the graph.No, t

Neko [114]

Answer:

a) (1, 2) not on the graph.

b) (1, -1) is on the graph.

Step-by-step explanation:

Given the equation of the line as:

$2x - y - 3 = 0$

The points given are

a) (1, 2)

To determine whether it is on the graph of the line or not.

To do so, we can do 2 things:

1. Draw the graph and plot the point on the graph to check whether it is on the graph or not.

2. To put the point in the given equation of the line, whether the equation is satisfied or not.

For method 1: Kindly refer to the attached image of the line and point plotted.

Method 2:

Let us put $x=1, y=2$ in the Left Hand Side (LHS) of equation.

$2\times 1 - 2 - 3\\\Rightarrow -3 \neq 0 , RHS$

(1, 2) Not on the graph.

(b) (1, -1)

For method 1: Kindly refer to the attached image of the line and point plotted.

Method 2:

Let us put $x=1, y=-1$ in the Left Hand Side (LHS) of equation.

$2\times 1 - (-1) - 3\\\Rightarrow 3-3 = 0 = RHS$

(1, -1) is on the graph.

3 0

4 years ago