Answer:
Step-by-step explanation:
Okay, so I think I know what the equations are, but I might have misinterpreted them because of the syntax- I think when you ask a question you can use the symbols tool to input it in a more clear way, otherwise you can use parentheses and such.
Problem 1:
(x²)/4 +y²= 1
y= x+1
*substitute for y*
Now we have a one-variable equation we can solve-
x²/4 + (x+1)² = 1
x²/4 + (x+1)(x+1)= 1
x²/4 + x²+2x+1= 1
*subtract 1 from both sides to set equal to 0*
x²/4 +x^2+2x=0
x²/4 can also be 1/4 * x²
1/4 * x² +1*x² +2x = 0
*combine like terms*
5/4 * x^2+2x+ 0 =0
now, you can use the quadratic equation to solve for x
a= 5/4
b= 2
c=0
the syntax on this will be rough, but I'll do my best...
x= (-b ± √(b²-4ac))/(2a)
x= (-2 ±√(2²-4*(5/4)*(0))/(2*(5/4))
x= (-2 ±√(4-0))/(2.5)
x= (-2±2)/2.5
x will have 2 answers because of ±
x= 0 or x= 1.6
now plug that back into one of the equations and solve.
y= 0+1 = 1
y= 1.6+1= 2.6
Hopefully this explanation was enough to help you solve problem 2.
Problem 2:
x² + y² -16y +39= 0
y²- x² -9= 0
Answer:
2 and 3
Step-by-step explanation:
prime numbers=2,3,4,5,...
taking 2 and 3
2+3=5
5²=25
hence the different prime numbers are 2 and 3
Answer: True.
The ancient Greeks could bisect an angle using only a compass and straightedge.
Step-by-step explanation:
The ancient Greek mathematician <em>Euclid</em> who is known as inventor of geometry.
The Greeks could not do arithmetic. They had only whole numbers. They do not have zero and negative numbers.
Thus, Euclid and the another Greeks had the problem of finding the position of an angle bisector.
This lead to the constructions using compass and straightedge. Therefore, the straightedge has no markings. It is definitely not a graduated-rule.
As a substitute for using arithmetic, Euclid and the Greeks learnt to solve the problems graphically by drawing shapes .
Answer:
See explanation
Step-by-step explanation:
1. To rewrite the expression

use exponents property

So,

2. Why ![10^{\frac{1}{3}}=\sqrt[3]{10}?](https://tex.z-dn.net/?f=10%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%3D%5Csqrt%5B3%5D%7B10%7D%3F)
Raise both sides to 10 power:
![(10^{\frac{1}{3}})^3=10^{\frac{1}{3}\cdot 3}=10^1=10\\ \\(\sqrt[3]{10})^3=10](https://tex.z-dn.net/?f=%2810%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%29%5E3%3D10%5E%7B%5Cfrac%7B1%7D%7B3%7D%5Ccdot%203%7D%3D10%5E1%3D10%5C%5C%20%5C%5C%28%5Csqrt%5B3%5D%7B10%7D%29%5E3%3D10)
So,
![(10^{\frac{1}{3}})^3=(\sqrt[3]{10} )^3](https://tex.z-dn.net/?f=%2810%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%29%5E3%3D%28%5Csqrt%5B3%5D%7B10%7D%20%29%5E3)
3. Simplify 
Use the Quotient of Powers Property:

Then

4. Solve 
First, note that
then

Number
is irrational number, number 10 is rational number. The sum of irrational and rational numbers is irrational number.
5. The same as option 4.
The correct proportion is 16/36=12/27