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Hatshy [7]
3 years ago
14

Best time to study math is morning or night? can y'all answer me bout what do you think?

Mathematics
1 answer:
Jlenok [28]3 years ago
5 0
I like studying in the evening, but if I had to choose, I'd study at night. In the morning my mind is asleep.
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What is m∠A to the nearest degree?
Anuta_ua [19.1K]
So this is a right triangle so you can use sin, cosine, or tangent. for A, you have the sides opposite and hypotenuse, which means you use sin*
sin(A) = opposite / hypotenuse
sin(A) = 56 / 75
arcsin(56/75) = A
A= about 48.3
so to the nearest degree, your answer is 48

*soh cah toa (if you dont know what that is, i can explain it)
4 0
2 years ago
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Andrea wants to deposit money into a bank account that earns 4.5% simple interest. Use the formula l=Prt to find the ammount of
AlladinOne [14]
The formula is
I=prt
I interest earned 2800
P amount deposited. ?
R interest rate 0.045
T time 4.5 years
Solve the formula for p by dividing both sides by rt to get
P=I/rt
P=2,800÷(0.045×4.5)
P=13,827.16 round your answer to get 13827

Hope it helps!
4 0
3 years ago
What is larger 27 feet 7 yards or 312 inches
olga2289 [7]

312 inches in feet: 26

7 yards in feet: 21 ft

<h2><u>2</u><u>7</u><u> </u><u>FT</u><u>!</u></h2>

6 0
3 years ago
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Litter such as leaves falls to the forest floor, where the action of insects and bacteria initiates the decay process. Let A be
Travka [436]

Answer:

D = L/k

Step-by-step explanation:

Since A represents the amount of litter present in grams per square meter as a function of time in years, the net rate of litter present is

dA/dt = in flow - out flow

Since litter falls at a constant rate of L  grams per square meter per year, in flow = L

Since litter decays at a constant proportional rate of k per year, the total amount of litter decay per square meter per year is A × k = Ak = out flow

So,

dA/dt = in flow - out flow

dA/dt = L - Ak

Separating the variables, we have

dA/(L - Ak) = dt

Integrating, we have

∫-kdA/-k(L - Ak) = ∫dt

1/k∫-kdA/(L - Ak) = ∫dt

1/k㏑(L - Ak) = t + C

㏑(L - Ak) = kt + kC

㏑(L - Ak) = kt + C'      (C' = kC)

taking exponents of both sides, we have

L - Ak = e^{kt + C'} \\L - Ak = e^{kt}e^{C'}\\L - Ak = C"e^{kt}      (C" = e^{C'} )\\Ak = L - C"e^{kt}\\A = \frac{L}{k}  - \frac{C"}{k} e^{kt}

When t = 0, A(0) = 0 (since the forest floor is initially clear)

A = \frac{L}{k}  - \frac{C"}{k} e^{kt}\\0 = \frac{L}{k}  - \frac{C"}{k} e^{k0}\\0 = \frac{L}{k}  - \frac{C"}{k} e^{0}\\\frac{L}{k}  = \frac{C"}{k} \\C" = L

A = \frac{L}{k}  - \frac{L}{k} e^{kt}

So, D = R - A =

D = \frac{L}{k} - \frac{L}{k}  - \frac{L}{k} e^{kt}\\D = \frac{L}{k} e^{kt}

when t = 0(at initial time), the initial value of D =

D = \frac{L}{k} e^{kt}\\D = \frac{L}{k} e^{k0}\\D = \frac{L}{k} e^{0}\\D = \frac{L}{k}

4 0
3 years ago
A recent poll of 80 randomly selected Californians showed that 38% ( = 0.38) believe they are doing all that they can to conserv
Elanso [62]
The margin of error given the proportion can be found using the formula

z* \sqrt{ \frac{p(1-p)}{n} }

Where
z* is the z-score of the confidence level
p is the sample proportion
n is the sample size

We have
z*=2.58
p=0.38
n=80

Plugging these values into the formula, we have:
2.58 \sqrt{ \frac{0.38(1-0.38)}{80} } =0.14

The result 0.14 as percentage is 14%

Margin error is 38% ⁺/₋ 14%
8 0
3 years ago
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