1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
-Dominant- [34]
3 years ago
10

Which has the greater value 0.3 or 1/3

Mathematics
2 answers:
xxMikexx [17]3 years ago
7 0
1/3, because that would be .33 in decimal terms, greater than .3
yulyashka [42]3 years ago
5 0
1/3 is greater than 0. 3
You might be interested in
Math ..................
Vaselesa [24]

It can work well here to simplify inside parentheses first.

\displaystyle\left(\frac{4x^{-2}y^{2}}{12x^{-4}y^{-1}}\right)^{3}=\left(\frac{4}{12}x^{(-2-(-4))}y^{(2-(-1))}\right)^{3}\\\\=\left(\frac{x^{2}y^{3}}{3}\right)^{3}=\frac{x^{(2\cdot 3)}y^{(3\cdot 3)}}{3^{3}}\\\\=\frac{x^{6}y^{9}}{27}

_____

The correct selection is not show with your problem statement.

7 0
3 years ago
Read 2 more answers
Help please this is my last one then I’m done and o get to do whatever I want because I’m done with my homework but I need this
Alexxandr [17]

Answer:

The answer is 4 + 3/6 + 2/6

Step-by-step explanation:

3 0
3 years ago
Find the dimensions of the open rectangular box of maximum volume that can be made from a sheet of cardboard 21 in. by 12 in. by
a_sh-v [17]

Answer:

Dimension of the box is 16.1\times 7.1\times 2.45

The volume of the box is 280.05 in³.

Step-by-step explanation:          

Given : The open rectangular box of maximum volume that can be made from a sheet of cardboard 21 in. by 12 in. by cutting congruent squares from the corners and folding up the sides.

To find : The dimensions and the volume of the box?

Solution :

Let h be the height of the box which is the side length of a corner square.

According to question,

A sheet of cardboard 21 in. by 12 in. by cutting congruent squares from the corners and folding up the sides.

The length of the box is L=21-2h

The width of the box is W=12-2h

The volume of the box is V=L\times W\times H

V=(21-2h)\times (12-2h)\times h

V=(21-2h)\times (12h-2h^2)

V=252h-42h^2-24h^2+4h^3

V=4h^3-66h^2+252h

To maximize the volume we find derivative of volume and put it to zero.

V'=12h^2-132h+252

0=12h^2-132h+252

Solving by quadratic formula,

h=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

h=\frac{-(-132)\pm\sqrt{132^2-4(12)(252)}}{2(12)}

h=\frac{132\pm72.99}{24}

h=2.45,8.54

Now, substitute the value of h in the volume,

V=4h^3-66h^2+252h

When, h=2.45

V=4(2.45)^3-66(2.45)^2+252(2.45)

V\approx 280.05

When, h=8.54

V=4(8.54)^3-66(8.54)^2+252(8.54)

V\approx -170.06

Rejecting the negative volume as it is not possible.

Therefore, The volume of the box is 280.05 in³.

The dimension of the box is

The height of the box is h=2.45

The length of the box is L=21-2(2.45)=16.1

The width of the box is W=12-2(2.45)=7.1

So, Dimension of the box is 16.1\times 7.1\times 2.45

6 0
3 years ago
HELP THIS IS DUE AT 12
kap26 [50]

Answer:

16

Step-by-step explanation:

4×.75=3

8×.75=6

16×.75=12

20×.75=15

7 0
2 years ago
Read 2 more answers
19, 38, 76, ... find the 8th term
Alisiya [41]
I think it’s 557

reasoning in pic

4 0
2 years ago
Other questions:
  • Please help thanks guys
    12·1 answer
  • Answer correctly for brainliest and also get a thanks ! Don't answer if you don't know it please :)
    10·2 answers
  • The equation of a circle is ​ (x−10)² + (y−8)² = 256 ​
    11·1 answer
  • Solve -2x + 6 = -20. -13 13 -7 7
    9·2 answers
  • D
    5·1 answer
  • 13/16 - 3/8 Perform the indicated operation.
    6·2 answers
  • Transform the equation if necessary, and then solve it to find the value of x that makes the equation true.
    15·2 answers
  • PLEASE HELP ME I DONT UNDERSTAND
    9·1 answer
  • The circumference of a circle is 25π cm. What is the area, in square centimeters? Express your answer in terms of \piπ.
    11·2 answers
  • PLEASE ANSWER !!
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!