Write an equation of the line that passes through the given point and has the given slope.

Mathematics

1 answer:

elena-14-01-66 [18.8K]4 years ago

6 0

Y-4 = -3 (x+5) (point slope form)

or

y= -3x-9 (y-intercept form)

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HELP!!! I WILL GIVE BRAINLIEST!!! 10 PTS!!!

tatiyna

Answer:

x= 55 degrees

w = 5

Step-by-step explanation:

Triangle PQR contains two triangles, QPS and PSR.

Looking at triangle QPS, it is an isosceles triangle. This is shown by the two short lines that cuts line QP and line QS.

In an isosceles triangle, two sides and two angles are equal. The two equal angles are the base angles.

Therefore,

angle P and angle S are equal. Also

Line QP and line PS are equal. This means

6w - 10 = w

6w-w = 10

5w = 10

w = 10/2 = 5

Angle Q + 100 degrees = 180 ( sum of angles on a straight line)

Angle Q = 180 - 100 = 80 degrees

Angle Q = Angle S(base angles of an isosceles triangle)

Angle PSR = 180 - 80 = 100 degrees( sum of angles on a straight line is 180)

Angle PSR + x + 25 = 180

x = 180 - 25 - 100 = 55 degrees

6 0

3 years ago

How are a ruler, a yardstick, and a measuring tape the same? How are they different?

QveST [7]

They all use the metric unit to measure things (e.g. inches, centimeters, etc.)
As far as I know, I think the difference might be that a yardstick only measures 1 yard. It has 36 inches (which is 3 feet, which is also 1 yard).
A ruler usually is only 12 inches.
A measuring tape is usually 12 feet.
That's what I know.

4 0

4 years ago

Read 2 more answers

Find, correct to four decimal places, the length of the curve of intersection of the cylinder 16x2 + y2 = 16 and the plane x + y

lubasha [3.4K]

First find a parameterization for the curve of intersection.

Given the equation of a cylinder, a natural choice for a parameterization would be one utilizing cylindrical coordinates. Here,

$16x^2+y^2=16\implies x^2+\left(\dfrac y4\right)^2=1$

which suggests we could use

$\begin{cases}x(t)=\cos t\\y(t)=4\sin t\\z(t)\end{cases}$

with $0\le t\le2\pi$ , and we get $z(t)$ from the equation of the plane,

$x+y+z=12\implies z(t)=12-x(t)-y(t)=12-\cos t-4\sin t$

Now use the arc length formula:

$\displaystyle\ell=\int_0^{2\pi}\sqrt{\left(\dfrac{\mathrm dx}{\mathrm dt}\right)^2+\left(\dfrac{\mathrm dy}{\mathrm dt}\right)^2+\left(\dfrac{\mathrm dz}{\mathrm dt}\right)^2}\,\mathrm dt$