A cube is packed with decorative pebbles. If the cube has a side length of 6 inches, and each pebble weighs on average 0.5 lb pe
2 answers:
Answer: 108 lbs.
Step-by-step explanation:
Given : A cube is packed with decorative pebbles. If the cube has a side length of 6 inches.
Volume of cube =
i.e. Volume of cube =
Since , each pebble weighs on average 0.5 lb per cubic inch.
Then, the total weight of the pebbles in the cube will be
= 0.5 x Volume of cube
=
Hence, the total weight of the pebbles in the cube =108 lbs.
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Answer:
There present ages are
Drex age = 17 years
Max age = 12 years
Step-by-step explanation:
Given as ,
The sum of age of Drex and Max = 29 years
And seven years ago Drex was twice as old as max
So , Let the Age of Drex = D and Max age = M
I.e (D - 7 ) = 2 (M - 7)
Or, D - 7 = 2M - 14
Or, 2M - D = 7
And Also D + M = 29
So , from both equations
(2M - D ) + (D + M) = 29 +7
Or, 3M = 36
I.e M = = 12 years
∴ The Age of Drex = 29 - M
The Age of Drex = 29 - 12 = 17 years
Hence there present ages are
The Age of Drex = 17 years
The Age of Max = 12 years Answer