Question

A cube is packed with decorative pebbles. If the cube has a side length of 6 inches, and each pebble weighs on average 0.5 lb per cubic inch, what is the total weight of the pebbles in the cube?

Answer 1

The volume of the cube is 6*6*6 (in cubed)=216 (in cubed).

    in 1 cubic inch, there is 0.5 lb of weight

so in 216 cubic inch, there are 216*0.5 lb = 108 lbs of weight  

Answer: 108 lbs

Answer 2

Answer: 108 lbs.

Step-by-step explanation:

Given : A cube is packed with decorative pebbles. If the cube has a side length of 6 inches.

Volume of cube = $(side)^3$

i.e. Volume of cube = $(6)^3=216\text{ cubic inches}$

Since , each pebble weighs on average 0.5 lb per cubic inch.

Then, the total weight of the pebbles in the cube will be

= 0.5 x Volume of cube

= $0.5\times216=108\text{ lb}$

Hence,  the total weight of the pebbles in the cube =108 lbs.