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kumpel [21]
4 years ago
6

I need help pweeeessss

Mathematics
1 answer:
yulyashka [42]4 years ago
5 0
4. x = 1/2 and y = 3

5. x = −5/7 and y = 16/7 

6. No solutions.

7. x = 7 and y = 4

8. ( You already got that one but just in case ) No solutions.

9. x = 3/2 and y = 3

10. x = 1/5 and y = 0

11. x = 3 and y = −8/5

12. x = −48 and y = −45

13. x = 92/15 and y = 29/15

14. x = −38/3 and y = 21 
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HELP URGANT WILL GIVE 20 POINTS AND BRAINLIEST FOR FAST AND ACCURATE ANSWER !!!
Kisachek [45]

The sine of any acute angle is equal to the cosine of its complement. The cosine of any acute angle is equal to the sine of its complement. of any acute angle equals its cofunction of the angle's complement.

A

C

B

Since m∠A = 22º is given, we know m∠B = 68º since there are 180º in the triangle. Since the measures of these acute angles of a right triangle add to 90º, we know these acute angles are complementary. ∠A is the complement of ∠B, and ∠B is the complement of ∠A.

If we write, m∠B = 90º - m∠A    (or m∠A = 90º - m∠B ), and we substitute into the original observation, we have:

7 0
4 years ago
A cargo plane flew roundtrip from Smithtown to Johnsville. It took one hour less time to get there than it did to get back. The
iren [92.7K]

Answer:

13 hours

Step-by-step explanation:

Average speed = Distance traveled / time taken

                   ⇒ Distance = Average speed × Time

                                     d = s × t

For the first trip;

Average speed = 280 mph

                          d₁ = 280t₁                    ------(1)

where;

d₁ is the distance covered to get to the destination

t₁ is the time taken to get to the destination

For the second trip;

Average speed = 240 mph

                           d₂= 240t₂                     ------(2)

where;

d₂ is the distance covered on the way back

t₂ is the time taken on the way back

The trip is the same distance to and fro. Therefore,

                           d₁ = d₂                              

Substituting the equation for d₁ and d₂

                          280t₁ = 240t₂              ------(3)

It took one hour less time to get there than it did to get back, then,

                                 t₁ = t₂ - 1

                                 t₂ = t₁ + 1                ------(4)

Substituting equation (4) into  equation (3)

                               280t₁ = 240(t₁ + 1)

                               280t₁ = 240t₁ + 240

                               280t₁ - 240t₁ = 240

                               40t₁ = 240

                                   t₁ = 240/40

                                   t₁ = 6 hours

From equation (4)

                                   t₂ = t₁ + 1

                                   t₂ = 6 + 1  

                                   t₂ = 7 hours

The total time for the trip is t₁ + t₂ = 6 + 7

                                       = 13 hours    

7 0
3 years ago
The table and graph both represent the same relationship. which equation also represents that relationship?
kow [346]

Answer:

I think it's y= 2x

Step-by-step explanation:

For every number in y, x increases by 2

4 0
3 years ago
Read 2 more answers
The formula for the lateral area of a right cone is LA = rs, where r is the radius of the base and s is the slant height of the
Usimov [2.4K]

Answer:

The equivalent ratios are:

s = \frac{LA}{r}s=

r

LA

r = \frac{LA}{s}r=

s

LA

The formula LA = rsLA=rs is given

In order to determine the equivalent ratios, make r the subject of the formula and s the subject of the formula in the above equation

To make s, the subject of the equation, divide both sides of the equation by r

s = \frac{LA}{r}s=

r

LA

To make r, the subject of the equation, divide both sides of the equation by s

r = \frac{LA}{s}r=

s

LA

Step-by-step explanation:

the Answer is Above The Image Or The Answer box

Thank's………………………………………………

7 0
2 years ago
Read 2 more answers
find the equation of the tangent to the curve y=x^2-2x-3 at the points where the line y=5 cuts the parabol​
olchik [2.2K]

ugh i hate tangents. never understood it

5 0
3 years ago
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