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kumpel [21]
3 years ago
6

I need help pweeeessss

Mathematics
1 answer:
yulyashka [42]3 years ago
5 0
4. x = 1/2 and y = 3

5. x = −5/7 and y = 16/7 

6. No solutions.

7. x = 7 and y = 4

8. ( You already got that one but just in case ) No solutions.

9. x = 3/2 and y = 3

10. x = 1/5 and y = 0

11. x = 3 and y = −8/5

12. x = −48 and y = −45

13. x = 92/15 and y = 29/15

14. x = −38/3 and y = 21 
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Please help!!! I will give brainliest to the person who explains it
artcher [175]
Since we know the degrees of the circle is 360, add all of the pieces together and set equal to 360
Solving you get x = 15.
When plugging 15 back into each expression we get 90, 160, and 110.
This means the triangle sides are all different so the triangle is scalene.
3 0
3 years ago
Please answer as fast as possible thanks
svp [43]

The correct answer is the 2nd choice because -1/6 is closer to 0 and the surface of the pool would be considered 0. -4/6 is farther away from 0 so it is less.

3 0
3 years ago
Round 60488 to the nearest ten thousand
ANTONII [103]
60,000 would be the answer because it stays the same if under 5 it stays if above 5 rounds up once
4 0
3 years ago
Read 2 more answers
Renee is wanting to join a gym.
WINSTONCH [101]
Pumping iron: 10x+90=0
Fit for life: 15x+50=0

Set them equal to each other. 10x+90=15x+50. Solve for x. Subtract 50 from both sides, get 10x+40=15x, then subtract 10x from both sides, getting 40=5x. Divide 5 from both sides to isolate x, x=8. After 8 months the two gyms will cost the same.
7 0
3 years ago
A truck weighing 150kN and travelling at 2m/sec impacts with a buffer
FrozenT [24]

The maximum compression of the spring is 0.276 m

Step-by-step explanation:

First of all, we calculate the spring  constant of the spring, by using Hooke's law:

F=kx

where

F = 10 kN = 10,000 N is the force applied

x = 1.25 cm = 0.0125 m is the corresponding compression of the spring

k is the spring constant

Solving for k,

k=\frac{F}{x}=\frac{10,000}{0.0125}=8\cdot 10^5 N/m

When the truck impacts with the spring, all the kinetic energy of the truck is converted into elastic potential energy of the spring, so we can write

\frac{1}{2}mv^2=\frac{1}{2}kx^2 (1)

where

m is the mass of the truck

v = 2 m/s is the initial speed of the truck

k=8\cdot 10^5 N/m is the spring constant

x is the compression of the spring

The mass of the truck can be found from its weight:

m=\frac{W}{g}=\frac{150,000 N}{9.81 N/kg}=15,290 kg

So now we can re-arrange eq.(1) to find the compression, x:

x=\sqrt{\frac{mv^2}{k}}=\sqrt{\frac{(15,290)(2)^2}{8\cdot 10^5}}=0.276 m

Learn more about kinetic energy:

brainly.com/question/6536722

#LearnwithBrainly

6 0
3 years ago
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