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Lady_Fox [76]
3 years ago
7

Ants are one of the lizard's favorite foods. it can eat 45 ants per minute. how long would it take this lizard to eat 1080 ants?

Express your answer in minutes.
Mathematics
2 answers:
Hatshy [7]3 years ago
7 0

Answer:

lizard can eat 1080 ants in 24 minutes.

Step-by-step explanation:

Consider the provided information,

lizard can eat 45 ants per minute.

45 ants = 1 minutes

We need to calculate how long would it take this lizard to eat 1080 ants.

Let x is the time taken by lizard to eat 1080 ants, thus

x=\frac{1080}{45}

x=24

Hence, lizard can eat 1080 ants in 24 minutes.

elena-14-01-66 [18.8K]3 years ago
3 0
1080 ants / 45 ants per minute = 24 minutes
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Let X1, X2 and X3 be three independent random variables that are uniformly distributed between 50 and 100.
sergejj [24]

Answer:

a) the probability that the minimum of the three is between 75 and 90 is 0.00072

b) the probability that the second smallest of the three is between 75 and 90 is 0.396

Step-by-step explanation:

Given that;

fx(x) = { 1/5 ; 50 < x < 100

              0, otherwise}

Fx(x) = { x-50 / 50 ; 50 < x < 100

                          1 ;   x > 100

a)

n = 3

F(1) (x) = nf(x) ( 1-F(x)^n-1

= 3 × 1/50 ( 1 - ((x-50)/50)²

= 3/50 (( 100 - x)/50)²

=3/50³ ( 100 - x)²

Therefore P ( 75 < (x) < 90) =  ⁹⁰∫₇₅ 3/50³ ( 100 - x)² dx

= 3/50³ [ -2 (100 - x ]₇₅⁹⁰

= (3 ( -20 + 50)) / 50₃

= 9 / 12500 = 0.00072

b)

f(k) (x) = nf(x)  ( ⁿ⁻¹_k₋ ₁) ( F(x) )^k-1 ; ( 1 - F(x) )^n-k

Now for n = 3, k = 2

f(2) (x) = 3f(x) × 2 × (x-50 / 50) ( 1 - (x-50 / 50))

= 6 × 1/50 × ( x-50 / 50) ( 100-x / 50)

= 6/50³ ( 150x - x² - 5000 )

therefore

P( 75 < x2 < 90 ) = 6/50³ ⁹⁰∫₇₅ ( 150x - x² - 5000 ) dx

= 99 / 250 = 0.396

3 0
2 years ago
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