Yes this is correct answer
27x^3 - 12x factors into
3(9x^3 - 4x) a common factor of three has been taken out.
3x(9x^2 - 4) a common factor of x has been taken out. 3x is not a linear factor.
9x^2 - 4 factors by means of the difference of squares
3x(3x - 2)(3x + 2)
The two linear factors are 3x - 2 and 3x + 2
Answer:
28 gallons
Step-by-step explanation:
We are given that a sports car gets 14mpg in city driving and 19mpg for highway.
The model G=
Where G=Amount of gasoline used (in gal) for c miles driven in the city and h miles driven on the high way.
Amount of gas used in 14 miles car in the city driving=1 gal
Amount of gas used in 1 mile car in the city driving=
Amount of gas used in c miles car in the city driving = gal
Similarly, for car driving on highway
Amount of gas used in h miles for car driving on highway=
c=98 miles in the city
h=399 miles on the highway
We have to find the amount of gas used required to derive 98 miles in the city and 399 miles on the highway.
Substitute the value of c and h in the given expression
Then, G=
Hence, the amount of gas required to derive 98 miles in the city and 399 miles on the highway=28 gallons
-4xy^6 * -3x = 12x^2y^6
-4xy^6 * 2y = -8xy^7
6 * -3x = -18x
6 * 2y = 12y
Answer = 12x^2y^6 + -8xy^7 + -18x + 12y