Answer:
(x−5y)(9x+8)
Step-by-step explanation:
9x^2−45yx+8x−40y
Do the grouping 9x^2−45yx+8x−40y=(9x^2−45yx)+(8x−40y), and factor out 9x in the first and 8 in the second group.
9x(x−5y)+8(x−5y)
Factor out common term x−5y by using distributive property.
(x−5y)(9x+8)
<span>3/20: 0.15
7/50: 0.14
9/25: 0.36
4/15: 0.266667
1/9: 0.111111
9/40: 0.225
5/16: 0.3125
7/9: 0.777778
13/20: 0.65
37/50: 0.74
11/30: 0.366667
19/40: </span>0.475
A) The longest horizontal distance is reached at 45 degrees angle. This is true for any projectile launch.
B) First, calculate fligth time (using the vertical motion) and then calculate the horizontal movement.
Flight time = 2* ascendent time
ascendent time => final vertical velocity, Vy, = 0
sin(45) = Voy / Vo => Voy = Vosin(45) = 25.5 m/s * (√2) / 2 = 18.03 m/s
Vy = Voy - gt = 0 => Voy = gt = t = Voy / g
Use g = 10 m/s^ (it is an aproximation, because the actual value is about 9.81 m/s^2 depending on the latitud)
t = 18.03 m/s / 10 m/s^2 = 1.83 s
This is the ascendant time going upward.
The flight time is 2*1.83 = 3.66 s
Horizontal motion
Horizontal velocity = Vx = constant = Vox = Vo*cos(45) = 18.03 m/s
Vx = x / t => x = Vx*t
Horizontal distance = xmax = 18.03m/s*3.66 s = 65.99 m
c) The time the ballon will be in the air was calculated in the part B, it is 18.03 s
Step-by-step explanation:
try the option shown in the attachment, note, all the answers are marked with red colour.
How much for 1lb
2.99/14=0.213/1=$0.21
it is 21 cents per lb