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leva [86]
3 years ago
7

Finn is baking cakes for a party. The number of cups of sugar Finn needs is proportional to the number of cakes he plans to bake

.
Which statements are true about the number of cups of sugar Finn needs?

Select each correct answer.

Finn needs 6 cups of sugar for 4 cakes.

Finn needs 4 cups of sugar for 6 cakes.

Finn needs 1 cup of sugar for 1 1/2 cakes.

Finn needs 1 1/2 cups of sugar for 1 cake.



99 points for the answer

Mathematics
2 answers:
FrozenT [24]3 years ago
5 0

The correct answer is Finn needs 6 cups of sugar for 4 cakes.

Hope this helped!! :)

Serhud [2]3 years ago
3 0

Note that it is proportional. The graph is given to you, in which the line includes all the points that can be answers. Find the point that is also given as a choice, and it is your answer.

Finn needs 6 cups of sugar for 4 cakes. is your answer

Note that it is in (x,y) format, and that y = cups of sugar, and x = cakes

hope this helps

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What are the zeros of the graphed function y = (x + 3)(x + 5)? –5 and –3 5 and 3 –8 and 5 0 and 5
Sati [7]

Answer:

Answers are:  (x+3)(x+5) = 0

So first zero:  x+3 = 0  so x = -3

Second zero: x+5 = 0 so x = -5

so zeros are: x = -5 and -3

Step-by-step explanation:

6 0
3 years ago
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Write the equation of the line that passes through (−3,1) and (2,−1) in slope-intercept form
Alex787 [66]

Answer:

y=-\frac{2}{5}x-\frac{1}{5}

Step-by-step explanation:

The equation of a line is y = mx + b

Where:

  • m is the slope
  • b is the y-intercept

First, let's find what m is, the slope of the line.

Let's call the first point you gave, (-3,1), point #1, so the x and y numbers given will be called x1 and y1.

Also, let's call the second point you gave, (2,-1), point #2, so the x and y numbers here will be called x2 and y2.

Now, just plug the numbers into the formula for m above, like this:

m = -\frac{2}{5}

So, we have the first piece to finding the equation of this line, and we can fill it into y=mx+b like this:

y=-\frac{2}{5}x + b

Now, what about b, the y-intercept?

To find b, think about what your (x,y) points mean:

  • (-3,1). When x of the line is -3, y of the line must be 1.
  • (2,-1). When x of the line is 2, y of the line must be -1.

Now, look at our line's equation so far: y=-\frac{2}{5}x + b. b is what we want, the --\frac{2}{5} is already set and x and y are just two 'free variables' sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the two points (-3,1) and (2,-1).

So, why not plug in for x and y from one of our (x,y) points that we know the line passes through? This will allow us to solve for b for the particular line that passes through the two points you gave!

You can use either (x,y) point you want. The answer will be the same:

  • (-3,1). y = mx + b or 1=-\frac{2}{5} * -3 + b, or solving for b: b = 1-(-\frac{2}{5})(-3).b = -\frac{1}{5}.
  • (2,-1). y = mx + b or -1=-\frac{2}{5} * 2 + b, or solving for b: b = 1-(-\frac{2}{5})(2). b = -\frac{1}{5}.

See! In both cases, we got the same value for b. And this completes our problem.

The equation of the line that passes through the points  (-3,1) and (2,-1) is y=-\frac{2}{5}x-\frac{1}{5}

8 0
2 years ago
The sum of an integer and 6 times the next consecutive odd integer is 61. Find the
vfiekz [6]

If the sum of an integer and 6 times the next consecutive integer is 61, the the value of lesser integer is 7

Consider the first odd integer as x

Then the next consecutive odd integer = x+2

The 6 times the second integer=  6(x+2)

= 6x+12

Sum of an integer and 6 times the next consecutive odd integer is 61

Then the equation will be

x + 6x+12 = 61

Add the like terms in the equation

(1+6)x + 12 = 61

7x +12 = 61

Move 12 to the right hand side of the equation

7x = 61-12

7x = 49

x = 49/7

x = 7

The second number is

x+2 = 7+2

= 9

Hence, if the sum of an integer and 6 times the next consecutive integer is 61, the the value of lesser integer is 7

Learn more about equation here

brainly.com/question/28741857

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Answer:

4 rides

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How did the graph of f(x) = x^2 and g(x) = 3/4 x^2 relate?
nirvana33 [79]

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<u>Step-by-step explanation:</u>

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Graphing y = (x - h)2 + k , where h = 0 & k = 0

Function g(x) can be formed with compression in function f(x) by a factor of 3/4 , i.e. g(x) = \frac{3}{4} f(x) or g(x) is 3/4 times of f(x).Domain and range of f(x) and g(x) are same ! Although structure of both functions is same the only difference is g(x) is compressed vertically by a factor 3/4. Both are graph of a parabola with vertex at (0,0). Also, F(x) and g(x) have common solution or intersecting point at x=0 i.e. in origin.

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3 years ago
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