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KonstantinChe [14]
3 years ago
7

at the local baseball diamond,the distance from home base to second base is 100 feet. Determine the distance from home base to f

irst base.
Mathematics
1 answer:
Archy [21]3 years ago
8 0

Answer:

  70.7 ft

Step-by-step explanation:

The triangle formed by home plate, first base, and second base is an isosceles right triangle with hypotenuse 100 ft. Then the side length (base-line distance between bases) is (100 ft)/√2 ≈ 70.7 ft.

___

For an isosceles right triangle with side lengths 1, the hypotenuse can be found from the Pythagorean theorem to be ...

  hypotenuse = √(side² + side²) = √(1²+1²) = √2

Then the diamond distances satisfy the proportion ...

  hypotenuse/side = 100 ft/(base distance) = √2/1

or ...

  base distance = (100 ft)/√2 ≈ 70.71068 ft

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Answer:

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Notice that there is a little triangle formed by the lines on the right side of the diagram.

Let's find the angle measures of the triangle. One of them has a supplementary angle of 96 degrees, which means that the actual interior angle is 180 - 96 = 84 degrees.

Another angle has a supplementary angle of 137, which means that the actual interior angle of the triangle is 180 - 137 = 43 degrees.

Finally, we have the expression 2x - 23, which is an exterior angle. By definition, this exterior angle is equal to the sum of the interior angles of the triangle that do not include its supplementary angle. In other words:

2x - 23 = 84 + 43

Now we just solve for x:

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