Multiply both sides of the equation by 3.
Subtract 6x on both sides.
Combine 2x and −6x to get −4x.
Add 20 to both sides. Any value plus zero results in its same value.
Divide both sides by −4.
Divide 20 by −4 to get −5.
What is the mode of the data represented in this line plot?
1 answer:
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The problem above uses a combination of sine and cosine law of triangle to solve for the m∠B.
Given:
<span>m∠A = 60°, b = 9 and c = 6
Cosine Law:
a^2=b^2+c^2-2bccosA
a^2=(9)^2+(6)^2-2(9)(6)cos(60)
a^2=81+36-54
a^2= 63
a=</span>
Sine Law
sin B= 9/ sin 60
sin B= 0.98198
B= sin ^-1 (0.98198) = 79.10
Therefore, m∠B is equal to 79.10
Given:
<span>m∠A = 60°, b = 9 and c = 6
Cosine Law:
a^2=b^2+c^2-2bccosA
a^2=(9)^2+(6)^2-2(9)(6)cos(60)
a^2=81+36-54
a^2= 63
a=</span>
Sine Law
sin B= 9/
sin B= 0.98198
B= sin ^-1 (0.98198) = 79.10
Therefore, m∠B is equal to 79.10