All categories

3 years ago

The graph below shows a system of equations:

Mathematics

2 answers:

svet-max [94.6K]3 years ago

8 0

Answer: -2

Step-by-step explanation:

We know that if system of two linear equations plotted on the graph, then the intersection point of the two lines represents the solution to the system of equations.

From the given graph , we can see that the intersection point of the two lines is at point (-2,2).

Thus, the solution to the given system of equation = (-2,2)

Therefore, the x-coordinate of the solution to the system of equations is -2.

Nostrana [21]3 years ago

4 0

3y = -2x + 2
y = x + 4 (Substitute the y)

3(x + 4) = -2x + 2 (Distribute)
3x + 12 = -2x + 2 (Add 3 to both sides)
+3x +3x
------------------------------------------
12 = 1x + 2 (Subtract 2 from both sides)
-2 - 2
------------------------
10 = 1x (Divide by 1 on both sides)
10/1 = 1x/1
x = 10
This is your x-coordinate

You might be interested in

Which point lies on the y-axis?

NeTakaya

Answer:

Step-by-step explanation:

3 0

2 years ago

SIMPLIFY THE EXPRESSION. 9(1 - 7x)

jok3333 [9.3K]

Answer:

9-63x

Step-by-step explanation:

9(1-7x)

9-63x

7 0

3 years ago

Read 2 more answers

Marty’s dog can run 3 miles in 20 minutes. What is the dog’s speed in miles per hour?

stich3 [128]

9mph because 20 minutes time 3 is one hour so multiply 3 by 3 to get 9

7 0

2 years ago

Read 2 more answers

an orange is divided into 6 equal wedges Jody eats 1 wedge then she eats 3 more wedges how much of the orange did Jody eat

chubhunter [2.5K]

Out of 6 wedges, Jody eats 4 wedges obviously so he eats 4/6 of the orange or to make it simple 2/3 of it

4 0

3 years ago

Read 2 more answers

A bin is constructed from sheet metal with a square base and 4 equal rectangular sides. if the bin is constructed from 48 square

kondaur [170]

This is a problem of maxima and minima using derivative.

In the figure shown below we have the representation of this problem, so we know that the base of this bin is square. We also know that there are four square rectangles sides. This bin is a cube, therefore the volume is:

V = length x width x height

That is:

$V = xxy = x^{2}y$

We also know that the bin is constructed from 48 square feet of sheet metal, so:

Surface area of the square base = $x^{2}$

Surface area of the rectangular sides = $4xy$

Therefore, the total area of the cube is:

$A = 48 ft^{2} = x^{2} + 4xy$

Isolating the variable y in terms of x:

$y = \frac{48- x^{2} }{4x}$

Substituting this value in V:

$V = x^{2}( \frac{48- x^{2} }{x}) = 48x- x^{3}$

Getting the derivative and finding the maxima. This happens when the derivative is equal to zero:

$\frac{dv}{dx} = 48-3x^{2} =0$

Solving for x:

$x = \sqrt{\frac{48}{3}} = \sqrt{16} = 4$

Solving for y:

$y = \frac{48- 4^{2} }{(4)(4)} = 2$

Then, the dimensions of the largest volume of such a bin is:

Length = 4 ft
Width = 4 ft
Height = 2 ft

And its volume is:

$V = (4^{2} )(2) = 32 ft^{3}$

8 0

2 years ago