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2 years ago

Y=2+4.3x when x=-6 I can’t figure this out

Mathematics

1 answer:

Ghella [55]2 years ago

7 0

Answer:

y=-23.8

Step-by-step explanation:

y=2+4.3(-6)

y=2+(-25.8)

y=-23.8

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In a sample of 679 new websites registered on the Internet, 42 were anonymous (i.e., they shielded their name and contact inform

Semmy [17]

Answer:

95% Confidence interval: (0.0429,0.0791)

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 679

Number of anonymous websites, x = 42

$\hat{p} = \dfrac{x}{n} = \dfrac{42}{679} = 0.0618$

95% Confidence interval:

$\hat{p}\pm z_{stat}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

$z_{critical}\text{ at}~\alpha_{0.05} = \pm 1.96$

Putting the values, we get:

$0.0618\pm 1.96(\sqrt{\dfrac{0.0618(1-0.0618)}{679}}) = 0.0618\pm 0.0181\\\\=(0.0429,0.0791)$

is the required confidence interval for proportion of all new websites that were anonymous.

8 0

2 years ago

Which is the simplified form of the expression?

Anon25 [30]

Given:

Consider the given expression is:

$10n-\dfrac{1}{3}(9n-12)$

To find:

The simplified form of the given expression.

Solution:

We have,

$10n-\dfrac{1}{3}(9n-12)$

Using distributive property, it can be written as:

$=10n-\dfrac{1}{3}(9n)-\dfrac{1}{3}(-12)$

$=10n-3n+4$

$=7n+4$

Therefore, the correct option is A.

4 0

3 years ago

Need help! According to the diagram below ABC is equivalent to XYZ by LL. we know that angle C and angle Z are because both are

aev [14]

I had this question and SAS is the correct answer

5 0

2 years ago

2 2/3 + 2 <br> By The Way, This is Fractions

Vilka [71]

4 2/3. add the twos and keep the 2/3

4 0

2 years ago

Water whose temperature is at 100∘C is left to cool in a room where the temperature is 60∘C. After 3 minutes, the water temperat

Tju [1.3M]

Answer:

21.68 minutes ≈ 21.7 minutes

Step-by-step explanation:

Given:

$T=60+40e^{kt}$

Initial temperature

T = 100°C

Final temperature = 60°C

Temperature after (t = 3 minutes) = 90°C

Now,

using the given equation

$T=60+40e^{kt}$

at T = 90°C and t = 3 minutes

$90=60+40e^{k(3)}$

$30=40e^{3k}$

$e^{3k}=\frac{3}{4}$

taking the natural log both sides, we get

3k = $\ln(\frac{3}{4})$

3k = -0.2876

k = -0.09589

Therefore,

substituting k in 1 for time at temperature, T = 65°C

$65=60+40e^{( -0.09589)t}$

$5=40e^{( -0.09589)t}$

$e^{( -0.09589)t}=\frac{5}{40}$

$e^{( -0.09589)t}=0.125$

taking the natural log both the sides, we get

( -0.09589)t = ln(0.125)

( -0.09589)t = -2.0794

t = 21.68 minutes ≈ 21.7 minutes

6 0

3 years ago