Answer:
ω = √((3g/L)*(1 - Cos θ))
Step-by-step explanation:
We need to apply the Principle of Conservation of mechanical energy as follows
Ei = Ef ⇒ Ki + Ui = Kf + Uf
In the vertical position
ωi = 0 ⇒ Ki = 0
yi = L/2 ⇒ Ui = m*g*L/2
We can get the rotational inertia I using the formula
I = m*L²/3
then
Kf = I*ω²/2 = (m*L²/3)*ω²/2 = m*L²*ω²/6
Now, we obtain the potential energy Uf as follows
Uf = m*g*y
where
y = (L/2)*Cos θ
⇒ Uf = m*g*(L/2)*Cos θ
Now, we have
Ui = Kf + Uf
⇒ m*g*L/2 = (m*L²*ω²/6) + (m*g*(L/2)*Cos θ)
⇒ ω² = (3g/L)*(1 - Cos θ)
⇒ ω = √((3g/L)*(1 - Cos θ))
We need to know the coefficient of static friction in order to get the value of theta where slip takes place.
Answer:
y=2/3x-2
Step-by-step explanation:
y-y1=m(x-x1)
y-(-6)=2/3(x-(-6))
y+6=2/3(x+6)
y=2/3x+12/3-6
y=2/3x+4-6
y=2/3x-2
Answer:
<h2>
10 units</h2>
Option C is the correct option
Step-by-step explanation:
Let the points be A and B
A ( 4 , 5 ) ------> ( x1 , y1 )
B ( 10 , 13 ) ------> ( x2 , y2 )
Now, let's find the distance between these points:
plug the values
Calculate the difference
Evaluate the power
Add the numbers
Write the number in exponential form with. base of 10
Reduce the index of the radical and exponent with 2
Hope this helps..
Best regards!!
