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KiRa [710]
3 years ago
6

3 x A = 30 + 30 it’s a 3rd grade problem but don’t know the answer

Mathematics
1 answer:
xenn [34]3 years ago
8 0

Answer: A=20

Step-by-step explanation:

3×A=30+30............eqn 1

3A=60

A=60/3

A=20

Substitute A=20 into equation 1

3x20= 30+30

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In ΔQRS, q = 6.8 inches, r = 1.9 inches and ∠S = 141° . Find the length of s, to the nearest 10th of an inch
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c = 141   s =

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Please help me solve all of these for M and B.
erastovalidia [21]

Answer:

In number 1:

m = 10/3

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Step-by-step explanation:

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for an acute angle 0, the equation sin(0) the equation sin(0) = cos(6) is true. What is the value of 0?​
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2 years ago
The figure shows a cylinder of diameter 12cm and height = 15cm. A hole in the shape of cone is bored into one of its end. If the
Lisa [10]

Answer:

\bold{495\pi} \approx \bold{1555.088 cm^3}

Step-by-step explanation:

There was no figure but the question is clear

Volume of a cylinder is given by the formula \bold{\pi r^2h}\\

where r is radius of base of cylinder, h is the height

Volume of a cone is given by \bold{\frac{1}{3} \pi r^2 h}

where r is the radius of base of cone, h is the height

The radius of the cylinder = \frac{1}{2}(diameter) = \frac{1}{2}(12) = 6cm

Height of cylinder = 15cm

Volume of cylinder V_{cyl} = \pi (6)^2  15 = \pi (36)15 = \bold{540\pi}

Radius of cone = \frac{1}{2} (radius of cylinder) = \frac{1}{2}(6) = 3 cm

Height of cone same as height of cylinder = 15cm

Volume of cone, V_{cone} = \frac{1}{3}\pi r^2 h = \frac{1}{3}\pi (3)^2 15 =  \frac{1}{3}(9)15\pi = \bold{45\pi}\\


Difference is the volume of the remaining solid

V_{cyl} - V_{cone} = 540\pi - 45\pi = \bold{495\pi} \approx \bold{1555.088 cm^3}



5 0
1 year ago
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