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3 years ago

HELP PLS ASAP I HAVE 6 MINUTES NO LINKS

Mathematics

1 answer:

Ainat [17]3 years ago

5 0

you could say if you knew how many cubes there were in total, you could subtract them

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Joan works in a clothing store. she earns a salary plus 10 percent of her sales revenue. this extra money that is expressed as a

Bad White [126]

the answer is commission

4 0

3 years ago

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Jose is selling peanuts at the carnival. The original bag he purchased weighs 6 3/4 lbs. If the bags he plans on selling will we

Aleks04 [339]

Answer:

13 bags

Step-by-step explanation:

1: If he has 6 3/4 lbs to start with, this is 6.75 lbs, as 3/4 = 0.75.

2: He wants the new bags to be 1/2 lb, which is 0.5 lbs.

3: If we divide 6.75 by 0.5, we get the exact number of bags he could have - 13.5.

4: However, the bags must be full, so we have to disregard that extra 0.5 bags, and say he can completely fill 13 bags.

Hope this helps! Let me know if you have any questions :)

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3 years ago

Refer to the isosceles trapezoid shown. Find x

lorasvet [3.4K]

X is 110 . Am I right

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3 years ago

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I NEED HELPPP ON THIS PLZZZ

Anika [276]

Answer:

Perimeter of ABCD = 56 units

Perimeter of WXYZ = 140 units

Step-by-step explanation:

To find the perimeter of ABCD, find the sum of all sides

18 + 18 + 10 + 10 = 56

To find the side lengths of WXYZ, use the equation: $\frac{image}{pre-image}$

45/18 = 2.5

You can also cross multiply to find the missing side lengths, but I'll show you this other way...

Multiply the pre-image side lengths by 2.5

18 × 2.5 = 45

10 × 2.5 = 25

45 and 25 of the new side length of WXYZ

To find the perimeter of WXYZ, find the sum of all sides.

45 + 45 + 25 + 25 = 140

WX = 45, XY = 25, YZ = 45, ZW = 25

3 0

3 years ago

A chemical company makes two brands of antifreeze. The first brand is 65% pure antifreeze, and the second brand is 90% pure anti

Brums [2.3K]

$\bf \begin{array}{lcccl} &\stackrel{solution}{gallons}&\stackrel{\textit{\% of }}{antifreeze}&\stackrel{\textit{gallons of }}{antifreeze}\\ \cline{2-4}&\\ \textit{1st brand}&x&0.65&0.65x\\ \textit{2nd brand}&y&0.90&0.9y\\ \cline{2-4}&\\ mixture&40&0.8&32 \end{array}~\hfill \to \begin{cases} x+y&=40\\ \boxed{x}=40-y\\ \cline{1-2} 0.65x+0.9y&=32 \end{cases} \\\\[-0.35em] ~\dotfill$

$\bf \stackrel{\textit{substituting in the 2nd equation}}{0.65\left( \boxed{40-y} \right)+0.9y=32}\implies 26-0.65y+0.9y=32 \\\\\\ 26+0.25y=32\implies 0.25y=6\implies y=\cfrac{6}{0.25}\implies \blacktriangleright y=24 \blacktriangleleft \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{since we know that}}{x=40-y\implies }x=40-24\implies \blacktriangleright x=16 \blacktriangleleft$

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3 years ago

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