The perimeter of a rectangle is 96 ft. Find the dimensions of the rectangle if the ratio of the length to the width is 7 : 5. Wh
ich of the following would be the best equation to use to solve this problem? Please show me how you got the answer too please if possible! Thank you!! A) 2x + 2x = 96
B) 7x + 5x = 96
C) 2(7x) + 2(5x) = 96
D) 7x/5x = 96
Lets say we have a rectangle. if the ratio is 7:5, we can put the width as 7x, and the length as 5x (or vice versa, it doesn't really matter.) If the perimeter is solved by 2(h+w), we have 2(7x+5x)=96, or 2(7x)+2(5x)=96, which is C
Step-by-step explanation:have a rectangle. if the ratio is 7:5, we can put the width as 7x, and the length as 5x (or vice versa, it doesn't really matter.) If the perimeter is solved by 2(h+w), we have 2(7x+5x)=96, or 2(7x)+2(5x)=96, which is C
This is quite a neat question, with no fixed equation. Given that each person gives the other two enough money to double their cash, if Toy had 36 dollars beginning, and 36 at the end - presumably the cash of each person, ( their starting and original ) should be the same as well. Respectively each should be a multiple of 36 dollars.
Jan's " give away " = Ami + 36, Jan - 108, Toy + 72
Toy's " give away " = Ami + 72, Jan + 36, Toy - 108
Therefore, we can conclude that Ami = 144 at the start, presuming he gave away 108 dollars, with a remaining 36. Jan, having 144 dollars ( after having his 72 dollars doubled by Ami ) gives 36 to Ami to double his amount, and 72 to double Toy's doubled amount, remaining with 36 dollars. Now Ami has 72 dollars, Jan has 36, and Toy has 144. Then, Toy double's Ami and Jan's amount, giving away 72 and 36 dollars, remaining with 36 dollars himself. Therefore, Ami has 144 dollars, Jan has 72 dollars, and Toy has 36 dollars both at the beginning and end.
