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olga_2 [115]
3 years ago
8

Help please! Solve the system of equations. ​

Mathematics
1 answer:
Lelu [443]3 years ago
7 0

2 * x = 2 * 3 = 6

9 * y = 9 * 2 = 18

18 + 6 = 24

x = 3

y = 2

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Step-by-step explanation:

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Step-by-step explanation:

you should get your answer

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Hey can you please help me posted picture of question
prisoha [69]
The formula for the conditional probability is:

P(A|B)= \frac{P(A*B)}{P(B)}

This indicates the probability of event A, given that event B has already occurred.

Here P(A*B) indicates P(A∩B).

Using the given values, in the formula, we can write:

P(A|B)= \frac{ \frac{3}{10} }{ \frac{2}{5} }  \\  \\ 
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Therefore, option D is the correct answer.
5 0
3 years ago
A California water company has determined that the average customer billing is $1,250 per year and the amounts billed have an ex
Tcecarenko [31]

Answer:

a)

Mean \mu = \dfrac{1}{\lambda }= 1250

\lambda = \dfrac{1}{1250}

b)

P(X > 5000) = 0.0183

c)

P(X > 1250) =0.3679

Step-by-step explanation:

From the given information:

a.)

Mean \mu = \dfrac{1}{\lambda }= 1250

\lambda = \dfrac{1}{1250}

Let consider X to be a random variable that follows an exponential distribution; then:

P(X) = 1 - e^{- \lambda x}   since \lambda > 0

b.)

The required probability that a random chosen customer would spend more than $5,000 can be computed as:

P(X > 5000) = 1  - \bigg [ 1 - e ^{- \dfrac{5000}{1250}}  \bigg]

P(X > 5000) =e^  {-4

P(X > 5000) = 0.0183

c.)

P(X > 1250) = 1  - \bigg [ 1 - e ^{- \dfrac{1250}{1250}}  \bigg]

P(X > 1250) =e ^{- 1

P(X > 1250) =0.3679

7 0
3 years ago
How do I graph the function: d(x)=|x| -4 ?​
777dan777 [17]

Answer:

attached below

Step-by-step explanation:

d(x)=|x| -4

x≥0   d(x) = x -4

x<0   d(x) = -x -4

6 0
2 years ago
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