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____ [38]
2 years ago
12

The wholesale price of a flower arrangement was $60 and the flowers were marked up 30%.

Mathematics
2 answers:
Anestetic [448]2 years ago
8 0

Answer:

A would be 18$ and B would be 78$

Step-by-step explanation:

i took this on edge

hope this helps <3

bye

noname [10]2 years ago
4 0

Step-by-step explanation:

I couldn't put this full page.

Thankfully I found the answer

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11. Solve.<br>10 =|4x+6]​
Mariulka [41]

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1

Step-by-step explanation:

10 = 4x+6

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4 0
3 years ago
Need help please our math teacher didn’t have enough time to give us the notes to learn this so I am confused
Fudgin [204]

Answers with step-by-step explanation:

1. (7x + x) + 7x

= 7x + 7x + x

= 14x + x

= 15x

2. 5 * (4 * x)

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= 20x

3. 15y + (x + 9y)

= 15y + 9y + x

= 24y + x

4. (6x + 21) + 14

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= 6x + 35

5. 3x + 2 + 11x

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= 14x + 2

6. (x + 13y) + 8y

= 13y + 8y + x

= 21y + x

7. (12y + 2x) + 4y

= 12y + 4y + 2x

= 16y + 2x

8. 8 (x4)

= 32x

9. 3 (5x)

= 15x

10. 3x + (7x + 10)

= 3x + 7x + 10

= 21x + 10

11. 5x + (2 + x)

= 6x + 2

12. 4 * x * 10

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= 40x

13. (x * 12) * 3

= 36x

14. 14x + 9y + 6x

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15. 5x + (24 + 14x)

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4 0
3 years ago
PTC is a substance that has a strong bitter taste for some people and is tasteless for others. The ability to taste PTC is inher
lana66690 [7]

Answer:

a) n=\frac{0.76(1-0.76)}{(\frac{0.01}{1.64})^2}=4905.83  

And rounded up we have that n=4906

b) For this case since we don't have prior info we need to use as estimatro for the proportion \hat p =0.5

n=\frac{0.5(1-0.5)}{(\frac{0.01}{1.64})^2}=6724  

And rounded up we have that n=6724

Step-by-step explanation:

We need to remember that the confidence interval for the true proportion is given by :  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

Part a

The estimated proportion for this case is \hat p =0.76

Our interval is at 90% of confidence, and the significance level is given by \alpha=1-0.90=0.1 and \alpha/2 =0.05. The critical values for this case are:

z_{\alpha/2}=-1.64, t_{1-\alpha/2}=1.64

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

The margin of error desired is given ME =\pm 0.01 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

Replacing we got:

n=\frac{0.76(1-0.76)}{(\frac{0.01}{1.64})^2}=4905.83  

And rounded up we have that n=4906

Part b

For this case since we don't have prior info we need to use as estimatro for the proportion \hat p =0.5

n=\frac{0.5(1-0.5)}{(\frac{0.01}{1.64})^2}=6724  

And rounded up we have that n=6724

3 0
3 years ago
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