A=Lw
P=2L+2w
216=Lw
W=216/L...substitute to Perimeter equation
60=2L+2(216/L)
60L=2L^2 + 432
2L^2-60L+432=0
2(L^2 - 30L + 216)=0
2(L-18)(L-12)=0
L=12, W=18 or L=18, W=12
Answer:
The second time when Luiza reaches a height of 1.2 m = 2 08 s
Step-by-step explanation:
Complete Question
Luiza is jumping on a trampoline. Ht models her distance above the ground (in m) t seconds after she starts jumping. Here, the angle is entered in radians.
H(t) = -0.6 cos (2pi/2.5)t + 1.5.
What is the second time when Luiza reaches a height of 1.2 m? Round your final answer to the nearest hundredth of a second.
Solution
Luiza is jumping on trampolines and her height above the levelled ground at any time, t, is given as
H(t) = -0.6cos(2π/2.5)t + 1.5
What is t when H = 1.2 m
1.2 = -0.6cos(2π/2.5)t + 1.5
0.6cos(2π/2.5)t = 1.2 - 1.5 = -0.3
Cos (2π/2.5)t = (0.3/0.6) = 0.5
Note that in radians,
Cos (π/3) = 0.5
This is the first time, the second time that cos θ = 0.5 is in the fourth quadrant,
Cos (5π/3) = 0.5
So,
Cos (2π/2.5)t = Cos (5π/3)
(2π/2.5)t = (5π/3)
(2/2.5) × t = (5/3)
t = (5/3) × (2.5/2) = 2.0833333 = 2.08 s to the neareast hundredth of a second.
Hope this Helps!!!
Answer:
Step-by-step explanation:
Answer:
Please see attached picture for full solution.
Answer:
The volume of cone v= 113.04 cm³.
Step-by-step explanation:
Formula used to find volume of cone is:
where r is the radius and h is the height of cone.
In the given question we are given:
height h= 6 cm
diameter d= 6 cm
We know radius r = d/2 = 6/2 = 3 cm
so, volume will be:
So, the volume of cone v= 113.04 cm³ given height h= 6cm and radius r= 3cm
