The area of a polygon = n*side^2 / (4 * tan(180/n))
where "n" is the number of sides

Let's calculate area for side = 2
area = 8*2^2 / (4 * tan(180/8))
area = 32 / (4 * tan(22.5))
area = 32 / 4*0.41421
 area = 19.3138746047 

Now, let's calculate area for side = 6
area = 8*6^2 / (4 * tan(180/8))
area = 288 / 1.65684 
area = 173.824871442 

 173.824871442 / 19.3138746047 = 9

So, the area would be 9 times larger.

ALSO, looking at the formula
n*side^2 / (4 * tan(180/n))
we can see that the side length appears just once in the formula and we are to square it in the calculation. So, if we increase the side length is increased by 3, then the area increases by 3^2 or 9.

5 0

4 years ago

Does anybody know the answer to those two questions

Anna11 [10]

Answer:

Question Number 2 is 20

Question number 3 is 18x-32

Step-by-step explanation:

7 0

4 years ago

3a-b=-9 -3a-2b=0 solve by elimination

anzhelika [568]

a = –2 and b = 3

Solution:

Given equations are

3a – b = –9 – – – – (1)

–3a – 2b = 0 – – – – (2)

To solve these equations by elimination method.

Elimination method means eliminating one variable to find the other variable.

Add equation (1) with equation (2), we get

3a – b + (–3a – 2b) = –9 + 0

⇒ 3a – b – 3a – 2b = –9

Combine like terms together.

⇒ 3a – 3a – b – 2b = –9

⇒ 0 – 3b = –9

⇒ – 3b = –9

Divide by (–3) on both sides, we get

⇒ b = 3

Substitute b = 3 in equation (1), we get

(1) ⇒ 3a – b = –9

⇒ 3a – 3 = –9

Add 3 on both sides of the equation,

⇒ 3a = –6

Divide 3 on both sides of the equation

⇒ a = –2

Hence, a = –2 and b = 3.

8 0

4 years ago