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lbvjy [14]
3 years ago
5

The area of a regular octagon is 35 cm 2 what is the area of a regular octagon with sides three times as large

Mathematics
1 answer:
Maurinko [17]3 years ago
5 0
The area of a polygon = n*side^2 / (4 * tan(180/n))
where "n" is the number of sides

Let's calculate area for side = 2
area = 8*2^2 / (4 * tan(180/8))
area = 32 / (4 * tan(22.5))
area = 32 / 4*0.41421
<span> <span> <span> area = 19.3138746047 </span> </span> </span>

Now, let's calculate area for side = 6
area = 8*6^2 / (4 * tan(180/8))
area = 288 / <span> <span> <span> 1.65684 </span> </span> </span>
area = <span> <span> <span> 173.824871442 </span> </span> </span>

<span> <span> 173.824871442 </span> / </span><span><span>19.3138746047 = </span> 9

So, the area would be 9 times larger.

ALSO, looking at the formula
</span>n*side^2 / (4 * tan(180/n))
we can see that the side length appears just once in the formula and we are to square it in the calculation.  So, if we increase the side length is increased by 3, then the area increases by 3^2 or 9.


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The region bounded by the given curves is rotated about the specified axis. Find the volume V of the resulting solid by any meth
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Answer:

\frac{128\pi}{3} cubic units

Step-by-step explanation:

We are given that a region bounded by a curves x=(y-7)^2

x=4 and about y=5

We have to find the value of volume of the resulting solid

To find the volume of resulting solid we are using cylinder method

Substitute the values of x then we get

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y-7=2  and y-7=-2

y=7+2=9 and y=-2+7=5

Radius of cylinder =r=y-5

and height =h=4-(y-7)^2=4-y^2-49+14 y=-y^2+14 y -45

Using cylinder method and integrate along y -axis from y=5 to y=9

Volume =\int_{a}^{b}2\pi r h dy=\int_{5}^{9}2\pi(y-5)(-y^2+14 y -45) dy

volume=2\pi\int_{5}^{9}(-y^3+19y^2-115y+225)dy

Volume =2\pi[-\frac{y^4}{4}+19\frac{y^3}{3}-115\frac{y^2}{2}+225y]^9_5

Volume =2\pi[-\frac{6561}{4}+\frac{625}{4}+19(\frac{729-125}{3})-115(\frac{81-25}{2})+225(9-5)]

Volume=2\pi(-1484+\frac{11476}{3}-3220+900)

Volume =2\pi(\frac{11476}{3}-3804)

Volume =2\pi(\frac{11476-11412}{3})=\frac{128\pi}{3}

Hence, volume of resulting solid =\frac{128\pi}{3} cubic units

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