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4 years ago

5

The area of a regular octagon is 35 cm 2 what is the area of a regular octagon with sides three times as large

1 answer:

Maurinko [17]4 years ago

5 0

The area of a polygon = n*side^2 / (4 * tan(180/n))
where "n" is the number of sides

Let's calculate area for side = 2
area = 8*2^2 / (4 * tan(180/8))
area = 32 / (4 * tan(22.5))
area = 32 / 4*0.41421
<span> <span> <span> area = 19.3138746047 </span> </span> </span>

Now, let's calculate area for side = 6
area = 8*6^2 / (4 * tan(180/8))
area = 288 / <span> <span> <span> 1.65684 </span> </span> </span>
area = <span> <span> <span> 173.824871442 </span> </span> </span>

<span> <span> 173.824871442 </span> / </span><span><span>19.3138746047 = </span> 9

So, the area would be 9 times larger.

ALSO, looking at the formula
</span>n*side^2 / (4 * tan(180/n))
we can see that the side length appears just once in the formula and we are to square it in the calculation. So, if we increase the side length is increased by 3, then the area increases by 3^2 or 9.

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Greatest common divisor of 24 ; 80 and 180 ?

Katarina [22]

Answer:

Step-by-step explanation:

1: GCF (72, 144, 180) = 36

2: GCF of 10 and 13 is 1.

3: GCF of 135, 45, and 25 is 5

4: GCF of 150 and 225 is 75

7 0

3 years ago

Last week the price of apples at a grocery store was $1.60 per pound. This week apples at the same grocery store on sale at 10%

daser333 [38]

First, let's find the discount.

1.60 * 0.1 = $0.16 (the discount)

Second, subtract the discount to the original price.

1.60 - 0.16 = $1.44 (price after discount was applied)

Third, multiply to 4 1/2 to find how much it will cost.

1.44 * 4.5 = $6.48 (price of 4 1/2 pounds of apples with discount applied)

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4 years ago

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Assoli18 [71]

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3 years ago

scoray [572]

C the variable T is the independent variable

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3 years ago

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Rounded to the nearest hundredth , what is the positive solution to the quadratic equation 0=2x^2+3x-8

elena-14-01-66 [18.8K]

The positive solution to the quadratic equation $2 x^{2}+3 x-8=0$ is x = 1.39

<h3><u>Solution:</u></h3>

Given quadratic equation is $2 x^{2}+3 x-8=0$

<em><u>The general quadratic equation is of form:</u></em>

$a x^{2}+b x+c=0$

Now comparing the general equation with the given equation we get

a = 2 , b = 3 and c = -8

<em><u>The formula to determine roots of the quadratic equation is:</u></em>

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

On plugging in vlaues, we get

$x=\frac{-3 \pm \sqrt{3^{2}-4 \times 2 \times(-8)}}{2 \times 2}$

$\mathrm{x}=\frac{-3 \pm \sqrt{9-(-64)}}{4}$

On solving we get,

$\begin{array}{l}{\mathrm{x}=\frac{-3 \pm \sqrt{9+64}}{4}} \\\\ {\mathrm{x}=\frac{-3 \pm \sqrt{73}}{4}}\end{array}$

$\mathrm{x}=\frac{-3+\sqrt{73}}{4} \text { OR } \mathrm{x}=\frac{-3-\sqrt{73}}{4}$

x = 1.39 OR x = -2.89

Hence , the positive solution to the quadratic equation is x = 1.39

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3 years ago