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lbvjy [14]
3 years ago
5

The area of a regular octagon is 35 cm 2 what is the area of a regular octagon with sides three times as large

Mathematics
1 answer:
Maurinko [17]3 years ago
5 0
The area of a polygon = n*side^2 / (4 * tan(180/n))
where "n" is the number of sides

Let's calculate area for side = 2
area = 8*2^2 / (4 * tan(180/8))
area = 32 / (4 * tan(22.5))
area = 32 / 4*0.41421
<span> <span> <span> area = 19.3138746047 </span> </span> </span>

Now, let's calculate area for side = 6
area = 8*6^2 / (4 * tan(180/8))
area = 288 / <span> <span> <span> 1.65684 </span> </span> </span>
area = <span> <span> <span> 173.824871442 </span> </span> </span>

<span> <span> 173.824871442 </span> / </span><span><span>19.3138746047 = </span> 9

So, the area would be 9 times larger.

ALSO, looking at the formula
</span>n*side^2 / (4 * tan(180/n))
we can see that the side length appears just once in the formula and we are to square it in the calculation.  So, if we increase the side length is increased by 3, then the area increases by 3^2 or 9.


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Number of flowers required = 1256

Step-by-step explanation:

Circumference of a circle is given by the formula,

Circumference = 2πr

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For a circle with radius = 100 in.

Therefore, circumference = 2π(100)

                                           = 200π

                                           = 628.32 ft

Distance between each flower = 6 in

                                                   ≈ \frac{6}{12}

                                                   = 0.5 ft

Number of flowers = \frac{\text{Circumference}}{\text{Space between each flower}}

                               = \frac{628.32}{0.5}

                               = 1256.63

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