2.5 pounds of grain cost ======= $1.75
∴ 5.3 pounds of grain will cost ===== (5.3×1.75)/2.5 = $3.71
This is the concept of relative speed; We are required to calculate the speed of the car and the bicycle.
Distance between the car and Bicycle=374 miles
Time they met=5.5 hr
Speed traveled by bicycle=x
Speed traveled by car=x+33.4334
Relative speed=x+(x+33.4334)=(2x+33.4334) mph
Distance=speed*time
374=(2x+33.4334)*5.5
374=11x+183.8837
collecting like term we get:
374-183.8837=11x
11x=190.1163
thus;
x=(190.1163)/(11)
x=17.2833 mph
thus the speed of the bicycle was x=17.2833 mph
The speed of the car was (x+33.4334)=(17.2833+33.4334)=50.7167 mph
Composing functions means that the input of the outer functions is the output of the inner function.
In fact, you can rewrite the circle notation as
![(f\circ g)(x)=f(g(x)),\quad (g\circ f)(x)=g(f(x))](https://tex.z-dn.net/?f=%28f%5Ccirc%20g%29%28x%29%3Df%28g%28x%29%29%2C%5Cquad%20%28g%5Ccirc%20f%29%28x%29%3Dg%28f%28x%29%29)
So, we can substitute g(x) with its expression:
![(f\circ g)(x)=f(g(x))=f(4x+2)](https://tex.z-dn.net/?f=%28f%5Ccirc%20g%29%28x%29%3Df%28g%28x%29%29%3Df%284x%2B2%29)
And since f(x)=x+5, we simply have to add 5 to its input:
![f(4x+2)=(4x+2)+5=4x+7](https://tex.z-dn.net/?f=f%284x%2B2%29%3D%284x%2B2%29%2B5%3D4x%2B7)
Similarly, we have, substituting f with its expression,
![(g\circ f)(x)=g(f(x))=g(x+5)](https://tex.z-dn.net/?f=%28g%5Ccirc%20f%29%28x%29%3Dg%28f%28x%29%29%3Dg%28x%2B5%29)
And since g(x)=4x+2, we have to multiply the input by 4 and add 2:
![g(x+5)=4(x+5)+2=4x+20+2=4x+22](https://tex.z-dn.net/?f=g%28x%2B5%29%3D4%28x%2B5%29%2B2%3D4x%2B20%2B2%3D4x%2B22)