Cell division happens twice during meiosis. One starting cell can produce for gametes (eggs or sperm.) In each round of division, cells go through four phases called prophase, metaphase, anaphase, and telophase.
prophase During prophase the chromosomes become visible as paired chromatids and the nuclear envelope disappears. This phase includes reduction division, which is where the number of chromosomes is decreased from 46 (diploid) to 23 (haploid.)
metaphase This is where the 23 remaining chromosomes become attached to the spindle fibers.
anaphase During this phase, the chromosomes move away from each other to one or the other pole of the spindle fiber.
telophase In which the chromatids or chromosomes move to opposite ends of the cell and two nuclei are formed.
interphase This is a resting period.
Answer:
Diversity of the community = 2.097
Explanation:
Given:
Number of pitch pines = 134
Number of douglas firs = 24
Number of red pines = 53
Find:
Diversity of the community
Computation:
Simpson's diversity index = N(N-1)/Σn(n-1)
Particular n n(n-1)
Pitch pine 134 17822
Douglas firs 24 552
Red pine 53 2756
Total N=211 21130
So,
D= [211(211-1)] / 21130
D = 2.097
Diversity of the community = 2.097
Answer:
The correct answer is option C. "Longer beaks allow the birds to better access seeds in bird feeders".
Explanation:
Since climate change makes more difficult for "<em>Parus major</em>" birds to feed from its primary source of food in gardens, the birds are adapting to access their second source of food, which is the bird feeder. Longer beaks allow the birds to better access seeds in bird feeders, therefore, the birds are developing longer beaks in order to adapt to their new conditions.
Explanation:
I think it fulse
I am positive, good luck man.
83.235 grams of CaCl2 is required to make 1 litre of 0.75M solution.
Explanation:
Molarity or molar concentration is the number of moles of solute that can be dissolved in 1 L of a solution.
let us find the number of moles
n=C*V Concentration is 0.75M
Volume is 1000ml.
n= 0.75*1
n= 0.75
This means there are 0.75 moles of CaCl2 in 1000 ml of solution of .75M.
Molar mass of CaCl2 is = 40.08+ 2(35.5)
= 110.98 gms
Thus 1 MOLE OF CaCl2 weighs 110.98
so 0.75 moles will weigh 110.98*0.75
= 83.235 grams of CaCl2 is required to make 1 litre of 0.75M solution.
