Answer:
The volume in such a package is 27648 in³
Step-by-step explanation:
Consider the provided information.
Postal regulations specify that a parcel sent by priority mail may have a combined length and girth of no more than 144 in.
Let the dimension are x by x by y.
Where x is the variable for the square base package and y is the variable for length.
Thus l=x, b=x and h=y
Then the volume of the box is: 
(∵V=lbh)
The maximum combined length and girth is 144.
Therefore, 
Substitute the value of y in volume of the box.
Substitute V'(x)=0.
Now apply second derivative test.
(Min)
(Max)
Hence, the maximum volume is at x=24
If x=24 then 
Substituting value of x = 24 and y = 48 gives 27648.
Hence, the volume in such a package is 27648 in³
A. 
To find greater than or smaller than relation, we multiply the terms like (numerator of L.H.S with denominator of R.H.S and put the value on the left side. Then multiply the denominator of L.H.S with numerator of R.H.S and put the value on right side. Now compare the digits.)
So, solving A, we get 810<209 ... This is false
B. 
= 238>589 ..... This is false
C. 
= 496>780 .... This is false
D. 
= 420<660 ..... This is true
Hence, option D is true.
Answer:
#1) 15*6*7=630CM^3
#2) (50)^3=50*50*50=125,000
Step-by-step explanation:
Trust me my answers are REAL <333
Answer:
use the formula of centroid that is
= x1+x2+x3/3
Answer:
see explanation
Step-by-step explanation:
Under a counterclockwise rotation about the origin of 90°
a point (x, y ) → (- y, x ), thus
P(1, - 1 ) → P'(1, 1 )
Q(3, - 2 ) → Q'(2, 3 )
R(3, - 4 ) → R'(4, 3 )
