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kifflom [539]
3 years ago
6

WILL GIVE BRAINLST HAVE AN AMAZING DAY :)

Mathematics
1 answer:
balandron [24]3 years ago
6 0

Answer:

what are we doing

Step-by-step explanation:

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How do the expressions 8+k2−6 and 8(k+2)−4k compare when k = 7?
Andreas93 [3]

Answer:

8+k2-6>8(k+2)-4k

Step-by-step explanation:

8+7×2-6 and 8(7+2)-4×7

8+14-16 and (56+16)-28

6 and 44

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2 years ago
What is the midpoint of the segment (-2,4) and (6,-4)
liberstina [14]
To find midpoint, we find the average or median of the two x terms and the average of the two y terms to find the right coordinate point. In this case, the average of -2 and 6 is 2, and the mean of 4 and -4 is 0, so the new coordinate point is (2,0).
3 0
2 years ago
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Define the term net income .. according to the given context​
Pachacha [2.7K]

ANSWER: the amount an individual earns after subtracting all expenses, taxes and costs.

4 0
3 years ago
Express each number in its simplest radical form. <br> √6⋅√60=?
Tom [10]

Answer:

6√10

Step-by-step explanation:

factorizing 6 and 60

6 =  2 x 3

60 = 2 x 2 x 3 x 5

hence

√6 · √60

= √ [ (2 x 3) · (2 x 2 x 3 x 5) ]

= √ (2· 2² · 3² · 5)

= √ (2² · 3²) x √(2·5)

= (2 · 3) x √10

= 6√10

5 0
2 years ago
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The 12th term of a sequence is 41 and the 15th term is 140. What is the nth term?
OLga [1]
An= mth term.
an=a₁+(n-1)*d

a₁₂=41
a₁₅=140

a₁₂=41
41=a₁+(12-1)*d
41=a₁+11d 
a₁+11d=41    (1)

a₁₅=140
140=a₁+(15-1)*d
140=a₁+14d 
a₁+14d=140    (2)

With the equiations (1) and (2)  build a system of equations
a₁+11d=41
a₁+14d=140

we solve it.
-(a₁+11d=41)
  a₁+14d=140
--------------------
       3d=99  ⇒d=99/3=33

a₁+11d=41
a₁+(11*33)=41
a₁+363=41
a₁=41-363=-322

an=a₁+(n-1)*d
an=-322+(n-1)*33
an=-322+33n-33
an=-355+33n

an=-355+33n

To check:
a₁₂=-355+33*12=-355+396=41
a₁₅=-355+33*15=-355+495=140.
3 0
3 years ago
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