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densk [106]
4 years ago
9

I think of a number multiply it by 2, subtract 5 and multiply the result by 2

Mathematics
1 answer:
zalisa [80]4 years ago
7 0
Call our original number n. Then here's what we did in an equation:
(n*2-5)*2=2

We can solve this for n:
n*2-5=1
n*2=6
n=3
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Find the zeroes of the polynomial function f(x)=x^4-5x^3+11x^2-25x+30.
katen-ka-za [31]

Step-by-step explanation:

x⁴ − 5x³ + 11x² − 25x + 30

x⁴ − 5x³ + 6x² + 5x² − 25x + 30

x² (x² − 5x + 6) + 5 (x² − 5x + 6)

(x² + 5) (x² − 5x + 6)

(x² + 5) (x − 2) (x −3)

The zeros are 2, 3, and ±√5i.

7 0
3 years ago
An automobile insurance company issues a one-year policy with a deductible of 500. The probability is 0.8 that the insured autom
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Answer:

y₀.₉₅ = 3659

Step-by-step explanation:

P( no accident ) = 0.8

P( one accident ) = 0

deductible = 500

mean = 3000

<u>Determine the 95th percentile of the insurance company payout </u>

Assuming : y =company payout , x =amount of loss incurred due to accident

Then :

P( x < 500 ) = 0.2 ( 1 - e^-500/3000)

                   = 0.2 ( 1 - e^-1/6 )

95th percentile =

= P( y < y₀.₉₅  ) 0.95

  P( y = 0 ) = 0.8 + 0.2 ( 1 - e^-1/6 ) = 0.8307

attached below is the remainder of the solution

5 0
3 years ago
Rudolph and the other reindeer are pulling Santa's sleigh that has a mass 1
finlep [7]

Answer:

it is 4.2 n

Step-by-step explanation:

because you have to divide 525/125=4.2

7 0
3 years ago
What is the most likely meaning of the word endangered?
schepotkina [342]

Answer:

exposed is another word for endangered

8 0
2 years ago
Read 2 more answers
4. Sandra has 35% of the money she needs. She has $105. How much more money does she need? Write the equation and solve.​
guajiro [1.7K]

Answer:

36.75

Step-by-step explanation:

First is turn the percent into a decimal which would be 0.35.

Then multiply 0.35 with 105

Finally this would equal to 36.75

Note: Hope I got it right, if I didn't I am very sorry this is all I can really do. If I did get it wrong please comment and I'll try again.

5 0
3 years ago
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