Answer:
Step-by-step explanation:
charge q1 is placed at x = 1.90 m and the charge q2 is placed at y = 1.15 m
here, the charge enclosed in a sphere is zero as the radius of sphere is 0.625 m which is less than the x = 1.90 m and y = 1.15 m. So by the Gauss's theorem,
where q is the charge enclosed, as the charge enclosed is zero so the electric flux is zero.
This is a problem involving the subtraction of two functions f(x) and g(x):
<span>if f(x)=3x-1 and g(x)=x+2, find (f-g)(x). In other words, find:
</span><span> f(x) = 3x-1
-{g(x) -(x+2)
-----------------
f(x) - g(x) = 3x - 1 - x - 2 = 2x - 3 (answer)</span>
(x - 8)³
(x - 8)(x - 8)(x - 8)
(x² - 8x - 8x + 64)(x - 8)
(x² - 16x + 64)(x - 8)
(x³ - 8x² - 16x² + 128x + 64x - 512)
x³ - 24x² + 192x - 512
Well if the second line was that much longer, you add the value of the first line to the second line SINCE the second line was THAT much longer.
Therefore 3 5/6 + 4 7/8 = 8 17/24 (total for second line)
Answer:
244.93
Step-by-step explanation:
area formula for trapezoid:1/2*(b1+b2)*h
area formula for semi circles: (3.14*r^2)/2
so then we cut the figure to make a semi cirlce and trapazoid
semicircle- 14 is the full diameter, divide by 2 to make 7, 7×3.14×7)/2=76.93
trapezoid: base one is 18. base 2 is 14. 18+14=32 then times that by 10.5 which is 336 and divide that by 2 is 168
add both and you get 244.93
