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leonid [27]
3 years ago
14

Please helppp!!!!!!! And please show your work so i can know what to do next time i have this same problem !

Mathematics
1 answer:
solmaris [256]3 years ago
4 0

Answer: The answer is $152.25

Step-by-step explanation:

First you multiply 0.07 by 163.71 to get 11.4597.

The you subtract 163.71 from 11.4597.

Then that's your answer. I hope this helped!

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For this case we must find a linear equation of the form:

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For the slope we have the following equation:

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Substituting values we have:

m = \frac {6-5} {1-1}\\m = \frac {1} {0}

We observe that the slope of the line is not defined.

Therefore, the line is vertical.

Thus, the equation of the line is given by:

x = 1

Answer:

The equation of the line is given by:

x = 1

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Answer:

  • Solution of equation ( x ) = <u>7</u>

Step-by-step explanation:

In this question we have given with an equation that is <u>4</u><u> </u><u>(</u><u> </u><u>5</u><u>x</u><u> </u><u>-</u><u> </u><u>2</u><u> </u><u>)</u><u> </u><u>=</u><u> </u><u>2</u><u> </u><u>(</u><u> </u><u>9</u><u>x</u><u> </u><u>+</u><u> </u><u>3 </u><u>)</u><u>.</u> And we are asked to solve this equation that means we have to find the value of <u>x</u><u>.</u><u> </u>

<u>Solution</u><u> </u><u>:</u><u> </u><u>-</u>

<u>\quad \longrightarrow \: 4 ( 5x - 2 ) = 2 ( 9x + 3 )</u>

<u>Step </u><u>1</u><u> </u><u>:</u> Removing parenthesis :

\quad \longrightarrow \:20x - 8 = 18x + 6

<u>Step </u><u>2</u><u> </u><u>:</u> Adding 8 from both sides :

\quad \longrightarrow \:20x - \cancel{ 8 }+  \cancel{8} = 18x + 6 + 8

On further calculations we get :

\quad \longrightarrow \:20x = 18x + 14

<u>Step </u><u>3 </u><u>:</u> Subtracting 18 from both sides :

\quad \longrightarrow \:20x - 18x =  \cancel{18x }+ 14 -  \cancel{18}

On further calculations we get :

\quad \longrightarrow \:2x = 14

<u>Step </u><u>4</u><u> </u><u>:</u> Dividing with 2 on both sides :

\quad \longrightarrow \: \frac{ \cancel{ 2}x}{ \cancel{2}}  =   \cancel{\frac{14}{2} }

On further calculations we get :

\quad \longrightarrow \:  \blue{\boxed{ \frak{x = 7}}}

  • <u>Therefore</u><u>,</u><u> </u><u>solution</u><u> </u><u>of </u><u>this </u><u>equation</u><u> </u><u>is </u><u>7</u><u> </u><u>or </u><u>we </u><u>can </u><u>say </u><u>that </u><u>value </u><u>of </u><u>this </u><u>equation</u><u> </u><u>is </u><u>7</u><u> </u><u>.</u>

<u>Verifying</u><u> </u><u>:</u><u> </u><u>-</u>

We are verifying our answer by substituting value of x in given equation. So ,

  • 4 ( 5x - 2 ) = 2 ( 9x + 3 )

  • 4 [ 5 ( 7 ) - 2 ] = 2 [ 9 ( 7 ) + 3 ]

  • 4 ( 35 - 2 ) = 2 ( 63 + 3 )

  • 4 ( 33 ) = 2 ( 66 )

  • 132 = 132

  • L.H.S = R.H.S

  • Hence, Verified.

<u>Therefore</u><u>,</u><u> </u><u>our </u><u>value</u><u> for</u><u> x</u><u> is</u><u> </u><u>correct </u><u>.</u>

<h2><u>#</u><u>K</u><u>e</u><u>e</u><u>p</u><u> </u><u>Learning</u></h2>
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DiKsa [7]

\bold{\huge{\blue{\underline{ Solution }}}}

<h3><u>Given </u><u>:</u><u>-</u></h3>

  • <u>The </u><u>right </u><u>angled </u><u>below </u><u>is </u><u>formed </u><u>by </u><u>3</u><u> </u><u>squares </u><u>A</u><u>, </u><u> </u><u>B </u><u>and </u><u>C</u>
  • <u>The </u><u>area </u><u>of </u><u>square </u><u>B</u><u> </u><u>has </u><u>an </u><u>area </u><u>of </u><u>1</u><u>4</u><u>4</u><u> </u><u>inches </u><u>²</u>
  • <u>The </u><u>area </u><u>of </u><u>square </u><u>C </u><u>has </u><u>an </u><u>of </u><u>1</u><u>6</u><u>9</u><u> </u><u>inches </u><u>²</u>

<h3><u>To </u><u>Find </u><u>:</u><u>-</u></h3>

  • <u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>area </u><u>of </u><u>square </u><u>A</u><u>? </u>

<h3><u>Let's </u><u>Begin </u><u>:</u><u>-</u><u> </u></h3>

The right angled triangle is formed by 3 squares

<u>We </u><u>have</u><u>, </u>

  • Area of square B is 144 inches²
  • Area of square C is 169 inches²

<u>We </u><u>know </u><u>that</u><u>, </u>

\bold{ Area \: of \: square =  Side × Side }

Let the side of square B be x

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

\sf{ 144 =  x × x }

\sf{ 144 =  x² }

\sf{ x = √144}

\bold{\red{ x = 12\: inches }}

Thus, The dimension of square B is 12 inches

<h3><u>Now, </u></h3>

Area of square C = 169 inches

Let the side of square C be y

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

\sf{ 169 =  y × y }

\sf{ 169 =  y² }

\sf{ y = √169}

\bold{\green{ y = 13\: inches }}

Thus, The dimension of square C is 13 inches.

<h3><u>Now, </u></h3>

It is mentioned in the question that, the right angled triangle is formed by 3 squares

The dimensions of square be is x and y

Let the dimensions of square A be z

<h3><u>Therefore</u><u>, </u><u>By </u><u>using </u><u>Pythagoras </u><u>theorem</u><u>, </u></h3>

  • <u>The </u><u>sum </u><u>of </u><u>squares </u><u>of </u><u>base </u><u>and </u><u>perpendicular </u><u>height </u><u>equal </u><u>to </u><u>the </u><u>square </u><u>of </u><u>hypotenuse </u>

<u>That </u><u>is</u><u>, </u>

\bold{\pink{ (Perpendicular)² + (Base)² = (Hypotenuse)² }}

<u>Here</u><u>, </u>

  • Base = x = 12 inches
  • Perpendicular = z
  • Hypotenuse = y = 13 inches

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

\sf{ (z)² + (x)² = (y)² }

\sf{ (z)² + (12)² = (169)² }

\sf{ (z)² + 144 = 169}

\sf{ (z)² = 169 - 144 }

\sf{ (z)² = 25}

\bold{\blue{ z = 5 }}

Thus, The dimensions of square A is 5 inches

<h3><u>Therefore</u><u>,</u></h3>

Area of square

\sf{ = Side × Side }

\sf{ = 5 × 5  }

\bold{\orange{ = 25\: inches }}

Hence, The area of square A is 25 inches.

6 0
2 years ago
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