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algol [13]
3 years ago
5

Need help ASAP :) Question on the picture:)

Mathematics
1 answer:
Sergio039 [100]3 years ago
3 0

Answer:

a. No

b. Yes

Step-by-step explanation:

a.

x - 4 = 12

x - 4 + 4 = 12 + 4

x = 16

16 ≠ 8

Therefore, the following value given for problem a is not a solution to the given equation.

b. (3 + x)/4 = 3

(3 + x)/4 * 4 = 3 * 4

3 + x = 12

3 + x - 3 = 12 - 3

x = 9

9 = 9

Therefore, the following value given for problem b is a solution to the given equation.

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Find the solution set.<br> x^2 – 5x = 0
Tom [10]

Answer:

x=0  and x=5

Step-by-step explanation:

x^2 – 5x = 0

Factor out an x

x(x-5) = 0

Using the zero product property

x=0 and x-5 =0

Solving

x=0 x-5+5 = 0+5

x=0  and x=5

8 0
3 years ago
What is first three common multiples of 4,9,and 12​
wel

Answer:

36 is the answer of this question

4 0
3 years ago
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Simplify the expression 2(x-6)+2(8)
jolli1 [7]

Answer:

2x+4

Step-by-step explanation:

Distribute:

=(2)(x)+(2)(−6)+(2)(8)

=2x+−12+16

Combine Like Terms:

=2x+−12+16

=(2x)+(−12+16)

=2x+4

8 0
3 years ago
An instructor who taught two sections of Math 161A, the first with 20 students and the second with 30 students, gave a midterm e
uranmaximum [27]

Answer:

<em>The answers are for option (a) 0.2070  (b)0.3798  (c) 0.3938 </em>

Step-by-step explanation:

<em>Given:</em>

<em>Here Section 1 students = 20 </em>

<em> Section 2 students = 30 </em>

<em> Here there are 15 graded exam papers. </em>

<em> (a )Here Pr(10 are from second section) = ²⁰C₅ * ³⁰C₁₀/⁵⁰C₁₅= 0.2070 </em>

<em> (b) Here if x is the number of students copies of section 2 out of 15 exam papers. </em>

<em>  here the distribution is hyper-geometric one, where N = 50, K = 30 ; n = 15 </em>

<em>Then, </em>

<em> Pr( x ≥ 10 ; 15; 30 ; 50) = 0.3798 </em>

<em> (c) Here we have to find that at least 10 are from the same section that means if x ≥ 10 (at least 10 from section B) or x ≤ 5 (at least 10 from section 1) </em>

<em> so, </em>

<em> Pr(at least 10 of these are from the same section) = Pr(x ≤ 5 or x ≥ 10 ; 15 ; 30 ; 50) = Pr(x ≤ 5 ; 15 ; 30 ; 50) + Pr(x ≥ 10 ; 15 ; 30 ; 50) = 0.0140 + 0.3798 = 0.3938 </em>

<em> Note : Here the given distribution is Hyper-geometric distribution </em>

<em> where f(x) = kCₓ)(N-K)C(n-x)/ NCK in that way all these above values can be calculated.</em>

7 0
3 years ago
30 POINTS! I NEED HELP
grin007 [14]
It is 0.5 my friend.
3 0
4 years ago
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