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levacccp [35]
3 years ago
12

Help!! Please help with this question.

Mathematics
2 answers:
adell [148]3 years ago
7 0

Answer:

The slope is 4

My logic:

Slope is delta y over delta x so if you take any 2 points on that graph and get the x and y of each point and find the change of the two x and the two y and put the change in y over the change in x. you get slope. like so= 16/4 or 4

Mashutka [201]3 years ago
6 0

Answer:

The slope seems to be 4.

Step-by-step explanation:

The line seems to be starting at (3,0) and if you use the rule rise/run, it goes up (rises) 4 units and moves over (runs) 1 unit. You then rewrite this as 4/1 and you get 4 as the slope!

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8.) A line passes through the points (k, 4) and (3, -6). The line is perpendicular to
amm1812

Answer:

K = 43

Step-by-step explanation:

We'll begin by determining the gradient of the equation 5y + 4x = 8. This can be obtained as follow:

5y + 4x = 8

Rearrange

5y = 8 – 4x

5y = –4x + 8

Comparing 5y = –4x + 8 with y = mx + c, the gradient m is –4

Next, we shall determine the gradient of the line perpendicular to the line with equation 5y = 8 – 4x.

This can be obtained as follow:

For perpendicular lines, their gradient is given by:

m1 × m2 = – 1

With the above formula, we can obtain the gradient of the line as follow:

m1 × m2 = – 1

m1 = –4

–4 × m2 = – 1

Divide both side by –4

m2 = –1/–4

m2 = 1/4

Finally, we shall determine the value of k as follow:

Coordinate => (k, 4) and (3, –6)

x1 coordinate = k

y1 coordinate = 4

x2 coordinate = 3

y2 coordinate = –6

Gradient (m) = 1/4

m = (y2 – y1) / (x2 – x1)

1/4 = (–6 – 4) / (3 – K)

1/4 = –10 /(3 – K)

Cross multiply

3 – K = 4 × –10

3 – K = –40

Collect like terms

– K = – 40 –3

–k = –43

Divide both side by – 1

K = –43/–1

k = 43

3 0
3 years ago
How many millimetres are there in 17cm?
wel
170 . 10 millimeters make up 1cm so multiple 17x10
5 0
3 years ago
Read 2 more answers
PLS HELP
mamaluj [8]
6... I think.
I hope that this is right
5 0
3 years ago
Read 2 more answers
A car was originally purchased in January 2010 for 27000 dollars. The car depreciates at a rate of 18% every year.
Maksim231197 [3]

Answer:

Number of year(n) = 3.4 year (Approx)

Step-by-step explanation:

Given:

Purchase value of car = $27,000

Depreciation rate per year (d) = 18% = 0.18

Future price = half of its original value = $27,000 / 2 = $13,500

Find:

Number of year(n) = ?

Computation:

Future price  =Purchase value(1-d)^n\\\\13,500=27,000(1-0.18)^n\\\\0.5=(0.82)^n\\\\n=3.444(Approx)

Number of year(n) = 3.4 year (Approx)

5 0
3 years ago
Compare the functions below f(x)=3^x+2 g(x)=20x+4 h(x)=2x^2+5x+2 select the true statements 1. Over the interval [2,3], the aver
Alex

2^2-4+6 is your answer

6 0
3 years ago
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