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2 years ago

Help!! Please help with this question.

Mathematics

2 answers:

adell [148]2 years ago

7 0

Answer:

The slope is 4

My logic:

Slope is delta y over delta x so if you take any 2 points on that graph and get the x and y of each point and find the change of the two x and the two y and put the change in y over the change in x. you get slope. like so= 16/4 or 4

Mashutka [201]2 years ago

6 0

Answer:

The slope seems to be 4.

Step-by-step explanation:

The line seems to be starting at (3,0) and if you use the rule rise/run, it goes up (rises) 4 units and moves over (runs) 1 unit. You then rewrite this as 4/1 and you get 4 as the slope!

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Va rog e urgent am nevoie de raspuns

Lady_Fox [76]

Answer: 4

Explanation:

f(x) = 2x - 1

f(√2) = 2√2 - 1

f(1) = 2(1) - 1

= 2 - 1

= 1

f(√3) = 2√3 - 1

*******************************************************

$\frac{f(\sqrt{2})-f(1)}{\sqrt{2}-1} +\frac{f(\sqrt{3})-f(\sqrt{2})}{\sqrt{3}-\sqrt{2}}$

= $\frac{(2\sqrt{2}-1)-1}{\sqrt{2}-1} +\frac{(2\sqrt{3}-1)-(2\sqrt{2}-1)}{\sqrt{3}-\sqrt{2}}$

= $\frac{2\sqrt{2}-2}{\sqrt{2}-1} +\frac{2\sqrt{3}-2\sqrt{2}}{\sqrt{3}-\sqrt{2}}$

= $\frac{2\sqrt{2}-2}{\sqrt{2}-1}(\frac{\sqrt{2}+1}{\sqrt{2}+1})+\frac{2\sqrt{3}-2\sqrt{2}}{\sqrt{3}-\sqrt{2}}(\frac{\sqrt{3}+\sqrt{2}}{\sqrt{3}+\sqrt{2}})$

= $\frac{4+2\sqrt{2}-2\sqrt{2}-2}{2 - 1} + \frac{6 +2\sqrt{6}-2\sqrt{6}-4}{3-2}$

= $\frac{2}{1} +\frac{2}{1}$

= 4

3 0

2 years ago

A 37 foot board must be cut into two parts. The longer part is one foot larger than the twice the shorter part. How long is each

Rus_ich [418]

Answer:

12 ft and 25 ft

Step-by-step explanation:

a part is x ft and the other is (2x+1) ft

so 37= x + 2x+1

37= 3x+1

-1 -1

36= 3x

:3 :3

x= 36:3

I= x= 12 ft

II= 2x+1=2*12+1=25 ft

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2 years ago

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jarptica [38.1K]

Answer:

in the pic

Step-by-step explanation:

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3 years ago

You run one lap around a mile track every eight minutes you're friend runs around the same track every 10 minutes. You both star

labwork [276]

10 , 20 , 30 , 40 , 50
8, 16 , 24, 32, 40

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3 years ago

Farmer Jones, and his wife, Dr. Jones, decide to build a fence in their field, to keep the sheep safe. Since Dr. Jones is a math

alex41 [277]

Answer: $\frac{8}{3}\times \sqrt{\frac{2}{5}}$

Step-by-step explanation:

Given two upward facing parabolas with equations

$y=6x^2 & y=x^2+2$

The two intersect at

$6x^2=x^2+2$

$5x^2=2$

$x^2$ = $\frac{2}{5}$

x= $\pm \sqrt{\frac{2}{5}}$

area enclosed by them is given by

A= $\int_{-\sqrt{\frac{2}{5}}}^{\sqrt{\frac{2}{5}}}\left [ \left ( x^2+2\right )-\left ( 6x^2\right ) \right ]dx$

A= $\int_{\sqrt{-\frac{2}{5}}}^{\sqrt{\frac{2}{5}}}\left ( 2-5x^2\right )dx$

A= $4\left [ \sqrt{\frac{2}{5}} \right ]-\frac{5}{3}\left [ \left ( \frac{2}{5}\right )^\frac{3}{2}-\left ( -\frac{2}{5}\right )^\frac{3}{2} \right ]$

A= $\frac{8}{3}\times \sqrt{\frac{2}{5}}$

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3 years ago