Pls solve this we need to find radius of this shape

Mathematics

1 answer:

Strike441 [17]3 years ago

5 0

(not sure )
my method
let projection of b onto line dq be M
BM is 2r
then let the remaining angle ( right) be K
in triangle BMK ,
MK = 29-5-r
By Pyth. theorem ,
23^2 = (2r)^2+(29-5-r)^2
529=4r^2+576-48r+r^2
5r^2-48r+47=0
r = 8.493237063 or 1.106762937(rejected)

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Find the matrix A of the linear transformation T(f(t))= 4f'(t)+6f(t) from P2 T0 P2 with respect to the standard basis of P2 {1,t

dimulka [17.4K]

Answer: The required matrix is

$A=\left[\begin{array}{ccc}6&4&0\\0&6&8\\0&0&6\end{array}\right] .$

Step-by-step explanation: The given linear transformation is

T(f(t)) = 4f'(t) + 6f(t).

We are to find the matrix A of T from P² to P² with respect to the standard basis P² = {1, t, t²}.

We have

$T(1)=4\times\dfrac{d}{dt}1+6\times1=0+6=6\times 1+0\times t+0\times t^2,\\\\T(t)=4\times\dfrac{d}{dt}t+6\times t=4+6t=4\times1+6\times t+0\times t^2,\\\\T(t^2)=4\times\dfrac{d}{dt}t^2+6\timest^2=8t+6t^2=0\times 1+8\times t+6\times t^2.$