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11111nata11111 [884]
3 years ago
10

NEED HELP PLZ ASAP WHAT IS X -6(-14+3x)-2x=144

Mathematics
2 answers:
NISA [10]3 years ago
8 0

Answer:

hi

Step-by-step explanation:

x=-3

vlabodo [156]3 years ago
4 0

Answer:

Its -3

Step-by-step explanation:

Hope this helped :)

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6 - 5 < X

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Write an algebraic expression that represents<br> the following phrase:<br> The product of 8 and 12
Ainat [17]

Answer:

8*12

Step-by-step explanation:

First, the problem asks for an expression; this means that there should be no equal sign. Also, the keyword "product" means that both the terms must be multiplied. So, 8*12 is the final expression; this equals 96.

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Quadrilaterals Graphic Organizer
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6 0
2 years ago
Perform the indicated operations. Reduce the answers to lowest terms .<br>​
kozerog [31]

Step-by-step explanation:

1. (2+4+1)/9 = 7/9

2. 2 1/3 + 2/3 = 2 + (1+2)/3 = 2 + 3/3 = 2+1 = 3

3. 1 1/5 + 2 3/5 = 1+2 + 1/5 + 3/5 = 3 + (1+3)/5 =

3 4/5

4. 5/6 + 2/10 + 1/5 = 5/6 + 1/5 + 1/5 = 5/6 + 2/5

= (5×5)/(6×5) + (2×6)/(5×6)

= 25/30 + 12/30

= (25+12)/30

= 37/30 = 1 7/30

5. 3 1/2 + 4 2/3

= 3+4 + 1/2 + 2/3

= 7 + (1×3)/(2×3) + (2×2)/(3×2)

= 7 + 3/6 + 4/6

= 7 + (3+4)/6 = 7 7/6 = 8 1/6

6. 9/13 - 5/13 = (9-5)/13 = 4/13

7. 7 6/8 - 5 2/8

= (7-5) + (6/8 - 2/8)

= 2 + 4/8

= 2 1/2

8. 2/3 - 3/7

= (2×7)/(3×7) - (3×3)/(7×3)

= 14/21 - 9/21 = (14-9)/21 = 5/21

9. 11 1/5 - 5 4/5

= 10 6/5 - 5 4/5

= (10-5) + (6/5 - 4/5)

= 5 + 2/5 = 5 2/5

10. 15 4/5 - 7 7/10

= (15-7) + (4/5 - 7/10)

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= 8 + 8/10 - 7/10

= 8 + 1/10

= 8 1/10

6 0
2 years ago
*In ∆ABC, on the extension of the side BC , draw a line segment CD ≅ CA . Draw the segment AD . The line segment CE is the angle
Leya [2.2K]

CE ⊥ CF because m∠ECA + m∠FCA = 90°

Step-by-step explanation:

In ∆ABC

  • On the extension of the side BC , draw a line segment CD ≅ CA
  • Draw the segment AD
  • The line segment CE is the angle bisector of ∠ACB
  • The line segment CF is the median towards AD in ∆ ACD

We want to prove that CF ⊥ CE

Look to the attached figure

In Δ ABC

∵ CE is the bisector of angle ACB

∴ ∠ACE ≅ ∠BCE

In Δ ACD

∵ CA = CD

∴ Δ ACD is an isosceles triangle

∵ AD is the median towards AD

- In any isosceles triangle the median from a vertex to its opposite

  side bisects this vertex

∴ AD bisects ∠ACD

∴ ∠ACF ≅ ∠DCF

∵ BCD is a straight segment

∵ CE , CA , CF are drawn from point C

∴ m∠BCE + m∠ACE + m∠ACF + m∠DCF = 180°

∵ m∠ACE ≅ m∠BCE

∵ m∠ACF ≅ m∠DCF

- Replace m∠BCE by m∠ACE and m∠DCF by m∠ACF

∴ m∠ACE + m∠ACE + m∠ACF + m∠ACF = 180°

∴ 2 m∠ACE + 2 m∠ACF = 180°

- Divide all terms by 2

∴ m∠ACE + m∠ACF = 90°

∴ EC ⊥ CF

CE ⊥ CF because m∠ECA + m∠FCA = 90°

Learn more:

You can learn more about perpendicular lines in brainly.com/question/11223427

#LearnwithBrainly

7 0
3 years ago
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