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Setler79 [48]
3 years ago
14

Let f be the function given by f(x=sin(5x pi/4

Mathematics
1 answer:
sasho [114]3 years ago
7 0
AP teachers for<span> course and exam preparation; permission </span>for<span> any other use ... 3. Question 2. Let f and g be the functions given by ( ). (. ) 2 1. </span>f x<span> x x. = − and. ( ) (. ) ..... </span>Let f be the function given by<span> ( ). ( ) </span>sin<span> 5. ,. </span>4<span>. </span>f x<span> x </span>π<span>. = + and let ( ). P x be the ...</span>
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A baseball diamond is a square with side 90 ft. A batter hits the ball and runs toward first base with a speed of 31 ft/s. (a) A
Afina-wow [57]

Answer:

13.86 ft/sec

Step-by-step explanation:

If we let x = distance batter has run at time t and  D = distance from second base to the batter at  time t, then we know \frac{dx}{dt}=31 ft/s and we want \frac{dD}{dt} when he is halfway (at x = 45).

Using Pythagoras theorem

D^2=90^2+(90-x)^2\\\text{Differentiating with respect to t}\\2D\frac{dD}{dt}=0+2(90-x)(-1)\frac{dx}{dt}\\2D\frac{dD}{dt}=-2(90-x)\frac{dx}{dt}

When x=45

D^2=90^2+(90-x)^2\\D^2=90^2+(90-45)^2\\D^2=10125\\D=\sqrt{10125}

2D\frac{dD}{dt}=-2(90-x)\frac{dx}{dt}\\2\sqrt{10125}\frac{dD}{dt}=-2(90-45)(31)\\\frac{dD}{dt}=\frac{-2(45)(31)}{2\sqrt{10125}} =-13.86ft/s

Thus, when the batter is halfway to first base, the distance between second base and the batter is  decreasing at the rate of about 13.86 ft/sec.

4 0
4 years ago
What is 3,567,194 rounded
coldgirl [10]
4,000,000 is 3,567,194 rounded (-:
4 0
3 years ago
What expression is equivalent to 184 + w + 237 + x
spin [16.1K]

Answer: w + x + 421

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
NEED HELP ASAP!!!!!!
solniwko [45]

Answer:

four sixths + three fifths.

Step-by-step explanation:

1 8/30 = 38/30.

4/6 + 3/5

= 20/30 + 18/30 = 38/30.

7 0
3 years ago
What is the value of x in the figure shown below? 65 35
sergeinik [125]

Answer:

the value of x is 30

Step-by-step explanation:

subtract the numbers and look on the graph.

4 0
3 years ago
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