QS would be 42. So the way i did it was I:
8x-51=3x-6
x=9
Plugged into both equations of QR and RS to then get the answer of 42
Answer: m = 10
.........................
Step-by-step explanation:
answer is 22 students in the team
<em>how </em><em>do </em><em>u </em><em>get </em><em>it? </em>
you know it is 80% of the students went for try out so you do 100% - 80% give you 20% students the number of students in the team already. so you do 20 / 100 x 110 students which already in the whole school over 1 which would give it 22
Answer
The LCM for 4xy², 2x²y3 is the numeric part 4 multiplied by the variable part.
4xy²
Step-by-step explanation:
First, using the order of operations(PEMDAS), you would solve what is inside the parenthesis.
<span>(8.218 + 9.93) + (17.782 + 0.07)
(</span>18.148) + (17.852)
18.148 + 17.852
Now, all you would have to do is add the two sums.
18.148 + 17.852 = <span>36
</span>
The answer would be 36.
I hope this helps!
