AE = AC = 4
m<CAB = 60 (equilateral triangle)
m<CAE = 90 (square)
m<BAE = 150 (= 60 + 90)
Triangle BAE is isosceles since AB = AE;
therefore, m<AEB = m<ABE.
m<AEB + m<ABE + m<BAE = 180
m<AEB + m< ABE + 150 = 180
m<AEB + m<AEB = 30
m<AEB = 15
In triangle ABE, we know AE = AB = 4;
we also know m<BAE = 150, and m<AEB = 15.
We can use the law of sines to find BE.
BE/(sin 150) = 4/(sin 15)
BE = (4 sin 150)/(sin 15)
BE = 7.727
The answer is (3,-4). On a graph you see it is right in the middle. Hope this helps.
<span>2x-4y=32
2x-8y=48
--------------subtract
4y = - 16
y = -4
</span>2x-4y=32
2x- 4(-4)=32
2x + 16 = 32
2x = 16
x = 8
answer
(8, -4)
2.95 * 10%=
2.95 * .1 =
.295
Subtract .295 from 2.95
2.95 - .295 = 2.655
$ 2.66
X is 6 that is the missing value in the equation
