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sukhopar [10]
3 years ago
13

438 people signed up for a city soccer league. The league places 15 people on each team. How many teams are there?

Mathematics
2 answers:
Stolb23 [73]3 years ago
6 0
You divide 438 by 15= 29.2 or 30
valentinak56 [21]3 years ago
5 0
438÷15= 22R8


15×10=150
15×10=150
15×2=30
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64×15=32×30 true or false
Dima020 [189]

\large \mathfrak{Solution : }

Yes, it's true because the value of LHS = RHS if we solve it .

  • 64 \times 15 = 32 \times 30

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4 0
3 years ago
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Can the numbers 24,32,40 be the lengths of the three sides of a right triangle? Explain why or why not
SpyIntel [72]

Answer:

Yes .The Pythagorean equation is true.

Step-by-step explanation:

yes, they can, because of the equation below :

a² = b² + c²

40² = 32² + 24²

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1600 = 1600 ✓

7 0
2 years ago
How to factor this expression <br><br>x^3 - 4x^2 + 4x - 16
Natalija [7]
X²(x - 4) +4 (x - 4)

(x² + 4) (x - 4)

First find the common terms that can enter into both x³ and 4x² then write its down in this case it’s x² that can enter x³ leaving only x _since x³/x² = subtract of the indices. x² will also enter 4x² leaving only four hence you having x² (x - 4)
then do the same for the next pair of terms giving you 4 that can enter into both 4 and 16
Leaving you with +4 (x - 4)

Now you can put the common terms together like so (x² + 4) and choose get one of the other two which are the same= (x - 4)
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8 0
3 years ago
Od<br> 2<br> (<br> 2 7 1-3<br> 1 3 1-2<br> 6:1-6<br> b =<br> d =<br> IDONE
Lena [83]

Answer:

a = \boxed{1},\: b=\boxed{0}\\\\c=\boxed{0},\: d=\boxed{1}

Step-by-step explanation:

  • \begin{bmatrix} 2 & 7\\\\1 & 3\end{bmatrix}\:\begin{bmatrix} -3 & 7\\\\1 & -2\end{bmatrix}=\begin{bmatrix} a & b\\\\c & d\end{bmatrix}

  • Multiply both the matrices on left side, we find:

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  • \rightarrow\begin{bmatrix} -6+7 & 14-14\\\\-3+3 & 7-6\end{bmatrix}=\begin{bmatrix} a & b\\\\c & d\end{bmatrix}

  • \rightarrow\begin{bmatrix} 1 & 0\\\\0 & 1\end{bmatrix}=\begin{bmatrix} a & b\\\\c & d\end{bmatrix}

  • Comparing the corresponding elements of both the matrices on both sides, we find:

  • a = \boxed{1},\: b=\boxed{0},\:c=\boxed{0},\: d=\boxed{1}
7 0
2 years ago
(x = 3)<br> y=x+5 <br> How would I solve this problem
Flura [38]
So it would be y=3+5 so you really just add 3+5 and that’s 8 so it would be y=8
5 0
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