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Lubov Fominskaja [6]
3 years ago
6

Jake made a wooden cone with a diameter of 6 inches and a height of 4.5 inches. What is the volume of this cone?

Mathematics
1 answer:
serious [3.7K]3 years ago
7 0

Answer:

42.42in³

Step-by-step explanation:

This problem bothers on the mensuration of solid shapes, a cone

Step one

We know that the volume of a cone is

V= 1/3πr²h

Given data

Diameter d= 6 inches

Radius r= diameter/2= 6/2= 3 inches

Height h = 4.5 inches

Step two

Substituting our given data we have

Volume = 1/3*3.142*3²*4.5

V= 1/3*3.142*9*4.5

V= 127.251/3

V= 42.42in³

You might be interested in
Solve:
mash [69]

Answer:

1. Infinitely Many Solutions

2. Zero Solutions

3. One Solution ( x = 6 )

Step-by-step explanation:

1.

12x + 8 = 2( 6x + 4 )

12x + 8 = 12x + 8

2.

2( 2x + 1 ) = 4x + 3

4x + 2 = 4x + 3

2 = 3

3.

4( x + 1 ) = 3x + 10

4x + 4 = 3x + 10

x + 4 = 10

x = 6

Hopefully this helps!

Brainliest please?

8 0
2 years ago
A sample of 114 mortgages approved during the current year showed that 36 were issued to a single-earner family or individual. T
kodGreya [7K]

Answer:

a-1) Reject H0 if zcalc > 1.645

a-2) z=\frac{0.316 -0.28}{\sqrt{\frac{0.28(1-0.28)}{114}}}=0.8561  

a-3) ii. False

b) ii. No

c) iii. n π > 10 and n(1 − π ) > 10

Step-by-step explanation:

1) Data given and notation

n=114 represent the random sample taken

X=36 represent the people that were issued to a single-earner family or individual

\hat p=\frac{36}{114}=0.316 estimated proportion of people that were issued to a single-earner family or individual

p_o=0.28 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

(a-1) H0: π ≤ .28 versus H1: π > .28. Choose the right option. Reject H0 if zcalc > 1.645 Reject H0 if zcalc < 1.645 a b

We need to conduct a hypothesis in order to test the claim that the true proportion is less than 0.28.:  

Null hypothesis:p\geq 0.28  

Alternative hypothesis:p < 0.28  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

The rejection zone would be on this case :

Reject H0 if zcalc > 1.645

Since is a right tailed test

(a-2) Calculate the test statistic. (Round intermediate calculations to 2 decimal places. Round your answer to 4 decimal places.) Test statistic

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.316 -0.28}{\sqrt{\frac{0.28(1-0.28)}{114}}}=0.8561  

(a-3) The null hypothesis should be rejected.

False, since our calculated value is less than our critical value we Fails to reject the null hypothesis

(b) Is this a close decision?

False the calculated value is significantly less than the critical value so we FAIL to reject the null hypothesis with enough confidence.

(c) State any assumptions that are required.

In order to satisfy the conditions we need the following two requirements:

iii. n π > 10 and n(1 − π ) > 10

And are satisfied:

114*0.28=31.92>10

114(1-0.28)=82,08>10

7 0
3 years ago
Can someone please teach me long division, and please provide examples.
Dmitrij [34]

Answer:

Step-by-step explanation:

Divide the tens column dividend by the divisor.

Multiply the divisor by the quotient in the tens place column.

Subtract the product from the divisor.

Bring down the dividend in the ones column and repeat.

okay so look at the image down below

8 0
2 years ago
When 23 is subtracted from 5 times a certain number the result is 87
allsm [11]
5x-23=87
add 23 to both sides
5x=110
divide both sides by 5
x=22

To check your answer...
5(22)-23=87
110-23=87
87=87
8 0
3 years ago
PPPPPPPPPPPLLLLLLLLLLLLLLLLZZZZZZZZZZZZZZ
svlad2 [7]
Easiest way is if you substitute each point (x,y) into each set of equations and both points work for both equations in the system of equations, then it is the correct answer

Otherwise substitute one equation for y in the other equation:
2x + 6 = x^2 + 5x + 6
-2x - 6. -2x -6
0 = x^2 + 3x. Factor
0 = x (x + 3)
Solve: x = 0. x + 3 = 0. ——> x = -3. Substitute into one original equation to get y value for
y = 2x + 6.
y = 2(0) + 6. y = 2(-3) + 6
y = 6. y = -6 + 6 —-> y = 0
(0 , 6) And. (-3 , 0)

4 0
3 years ago
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