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4 years ago

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Which expression of signed decimal numbers has a positive quotient?

1 answer:

melomori [17]4 years ago

7 0

Answer:

it would be -1.7 / -10.06 because if you divide 2 negative numbers than you get a positive number and if you divide a negative and a positive number than it would be negative

Hope this helps you ❤️

Step-by-step explanation:

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Assume that random guesses are made for seven multiple choice questions on an SAT test, so that there are n=7 trials, each with

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Answer:

P(X < 4) = 0.5

Step-by-step explanation:

For each question, there are only two possible outcomes. Either it is answered correctly, or it is not. The probability of a question being answered correctly is independent of any other question. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this question, we have that:

$n = 7, p = 0.5$

Find the probability that the number of correct answers is fewer than 4:

This is

$P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{7,0}.(0.5)^{0}.(0.5)^{7} = 0.0078$

$P(X = 1) = C_{7,1}.(0.5)^{1}.(0.5)^{6} = 0.0547$

$P(X = 2) = C_{7,2}.(0.5)^{2}.(0.5)^{5} = 0.1641$

$P(X = 3) = C_{7,3}.(0.5)^{3}.(0.5)^{4} = 0.2734$

$P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0078 + 0.0547 + 0.1641 + 0.2734 = 0.5$

So

P(X < 4) = 0.5

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