A is the correct answer because the parabolas never touch.
Step-by-step explanation:


Step-by-step explanation:
5. Let the equation of the line be y = mx + c
m = (6-15)/(2-(-1)) = -3
sub (2, 6) and m = -3:
6 = -3(2) + c
c = 12
Equation of the line: y = -3x + 12
6. Let the equation of the line be y = mx + c
y-intercept of 7 means c = 7
y = mx + 7
x-intercept: value of x when y = 0
therefore, sub (4, 0):
0 = m(4) + 7
m = -7/4
Equation of the line: y = -7/4x + 7
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Answer:
(5a - [2b - 7c]) and (5a + [2b + 7c])
Step-by-step explanation:
Factor 25a^2 - 4b^2 + 28bc - 49c^2.
Note that - 4b^2 + 28bc - 49c^2 involves the variables b and c, whereas 25a^2 has only one variable. Thus, try to rewrite - 4b^2 + 28bc - 49c^2 as the square of a binomial:
- 4b^2 + 28bc - 49c^2 = -(4b^2 - 28bc + 49c^2), or
-(2b - 7c)^2.
Thus, the original 25a^2 - 4b^2 + 28bc - 49c^2 looks like:
[5a]^2 - [2b - 7c]^2
Recall that a^2 - b^2 is a special product, the product of (a + b) and (a - b). Applying this pattern to the problem at hand, we conclude:
Thus, [5a]^2 - [2b - 7c]^2 has the factors (5a - [2b - 7c]) and (5a + [2b + 7c])
Answer:
i cant see it very well it is too small can you zoom it in some thx :)
Step-by-step explanation: