<img src="https://tex.z-dn.net/?f=%3Cbr%3E%0Ay%3D%20x%5E%7B2%7D%20-9" id="TexFormula1" title="&#10;y= x^{2} -9" alt="&#1

All categories

weqwewe [10]

3 years ago

0;y= x^{2} -9" align="absmiddle" class="latex-formula"> $y=x^{2} -9$

Mathematics

1 answer:

svp [43]3 years ago

7 0

Simple...

y= $x^{2} -9$

$y= x^{2} -9$

It's quite easy to see $x^{2} = x^{2}$

Thus, any value of x makes the equation true.

Thus, your answer.

You might be interested in

il63 [147K]

The required value after simplification of the s = -16/3. None of these are correct.

Given that,
To simplify $[\frac{x^{2/3}x^{-1/2}}{x\sqrt{x^3}\sqrt[3]{x}}]^2$ and to find the value of s in $x^s$ .

<h3>What is simplification?</h3>

The process in mathematics to operate and interpret the function to make the function simple or more understandable is called simplifying and the process is called simplification.

Simplification,

$=[\frac{x^{2/3}x^{-1/2}}{x\sqrt{x^3}\sqrt[3]{x}}]^2\\= \frac{x^{4/3}x^{-1}}{x^2x^3*{x}^{2/3}}\\= \frac{x^{1/3}}{x^{17/3}}\\=x^{-16/3}$
Comparing with $x^S$
s = -16/3