So we got the real axis and the imaginary axis
we just need to find the average of the 2 points
remember
midpoint of (x1,y1) and (x2,y2) is
((x1+x2)/2,(y1+y2)/2)
so
average of 3 and -8 is -5/2
average of -5i and 2i is -3/2i
center is -5/2-3/2i
The slope of the line is negative
1. The figure is a prism: V = lwh = (12.1)(5.3)(4.2) = 269.3 cu. cm.
2. The figure is also a prism but the base is triangular: V = 1/2*b*h*l = 1/2*(13)*(sqrt(3)/2*13)*24 = 1756.3 cu. yd.
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The solution is D.
By plugging the x value, 5, into the equation:
6*5=30
30+1=31
y=31
the x value is 5 and the y value is 31
(5, 31)
hope that helps!
Question 1:
For this case we have an equation of the form:
Where,
- <em>k: inverse variation constant.
</em>
Then, substituting values we have:
From here, we clear the value of k.
We have then:
Answer:
the constant of inverse variation is:
Question 2:
For this case we have:
Where,
- <em>k: constant of variation.
</em>
Then, substituting the value of the constant we have:
We now substitute the value of x:
Answer:
the value of y when x = 4 is:
