Ask question

Ask question

All categories

3 years ago

7

Plss answer correctly 4x - 8 - 2x = 10

2 answers:

Tom [10]3 years ago

5 0

The correct answer is x=9.

First, combine like terms. 2x-8=10

Second, add 8 on both sides. 2x+18

Last, divide both sides of the equation by 2. X=9

Hope this helps!

MissTica3 years ago

3 0

Answer:

x=9

Step-by-step explanation:

4x-8-2x=10

2x-8=10

2x=18

x=9

You might be interested in

Jennifer said the median of the set is 2, because it is the middle value in the data set. Explain why you do or do not agree wit

Sophie [7]

That is correct. The median is the middle value.

4 0

3 years ago

Read 3 more answers

What is the first step in solving the quadratic equation x2 = StartFraction 9 Over 16 EndFraction?

dlinn [17]

Step-by-step explanation:

${x}^{2} = \frac{9}{16} \\ first \: step : \: take \: square \: root \: of \: both \\ sides. \\ \sqrt{ {x}^{2} } = \pm \sqrt{\frac{9}{16} } \\ x = \pm \frac{3}{4} \\$

8 0

3 years ago

Read 2 more answers

The amounts of time employees of a telecommunications company have worked for the company are normally distributed with a mean o

Fynjy0 [20]

Answer:

a) 5.6 years

b) 0.4478

Step-by-step explanation:

We are given the following in the question:

Mean, μ = 5.6 years

Standard Deviation, σ = 1.9 years

Sample size, n = 18

We are given that the distribution of amounts of time is a bell shaped distribution that is a normal distribution.

a) Mean of each sample.

The best estimator of the sample mean is the population mean itself. Thus, we have:

$\mu_{x} = \mu = 5.6$

Thus, the sample mean is 5.6 years.

b) Standard error

Formula:

$S.E = \dfrac{\sigma}{\sqrt{n}}$

Putting values, we have.

$S.E = \dfrac{1.9}{\sqrt{18}} = 0.4478$

Thus, the standard error is 0.4478.

7 0

3 years ago

What is the least common multiple of 15, 24 and 27?

cricket20 [7]

The least common multiple is 3

8 0

4 years ago

Write and solve a math problem in which you need to find how many equal groups

Vlad1618 [11]

There are 32 students in the class. Separate them into 8 groups of 4

4 0

3 years ago