Answer:
Once. at (3,0)
Step-by-step explanation:
It is handy to have a graphing calculator for this kind of question.
Otherwise work it out.
All the terms are multiples of 3, so simplify.
then factor (x -3)(x-3)
Set each equal to 0 and solve for x.
x - 3 = 0 x = 3
OH ! they are identical! So there is only One value for x that will produce an output of 0.
So it intersects (touches) only once.
(-3j²k³)²(2j²k)³ = <em>When a power is raised to a power the exponents have to be multiplied.</em>
= (-3²j⁽²*²⁾k⁽³*²⁾)(2³j⁽²*³⁾k³) = <em>We can take out the constants</em>
= (9)(8)(j⁴k⁶)(j⁶k³) = <em>We can group the same variables</em>
= 72(j⁴j⁶)(k⁶k³) = <em>When multiplying two powers that have the same base, you have to add the exponents.</em>
= 72 j⁽⁴⁺⁶⁾k⁽⁶⁺³⁾ = 72j¹⁰k⁹
Answer = 72j¹⁰k⁹
Hope this helps!