Multiply and rewrite the system: 16푥−10푦=10 −8푥−6푦=6 solving for elimination
1 answer:
You might be interested in
<h2><u>Answer:</u></h2>
⟶ 2³ × 3² is the prime factorization for which one of these choices?
Let's check,
1) 6 = 3 × 2 [So, obviously not this choice]
2) 25 = 5 × 5 = 5² [Not this either]
3) 36 = 3 × 2 × 2 × 3 = 3² × 2² [Doesn't match with 2³ × 3²]
4) 72 = 2 × 2 × 2 × 3 × 3 = <u>2</u><u>³</u><u> </u><u>×</u><u> </u><u>3</u><u>²</u><u> </u>[Matches]
⟶ The answer is, choice <u>7</u><u>2</u><u>.</u>
Answer:
0.1131 = 11.31% probability that a randomly selected stock will close up $0.75 or more.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean and standard deviation
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Normally distributed with a mean of $0.35 and a standard deviation of $0.33.
This means that .
What is the probability that a randomly selected stock will close up $0.75 or more?
This is 1 subtracted by the p-value of Z when X = 0.75. So
has a p-value of 0.8869.
1 - 0.8869 = 0.1131
0.1131 = 11.31% probability that a randomly selected stock will close up $0.75 or more.