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chubhunter [2.5K]

3 years ago

8

If AD is the altitude to BC, what is the slope of AD?

1 answer:

anygoal [31]3 years ago

3 0

Answer:

Option (C)

Step-by-step explanation:

If AD is the altitude to BC, both the segments AD and BC will be perpendicular to each other.

By the property of perpendicular lines,

$m_1\times m_2=-1$

where $m_1$ is the slope of the line AD and $m_2$ is the slope of BC.

$m_2=\frac{y_2-y_1}{x_2-x_1}$

$=\frac{8+2}{3-7}$

$=-\frac{5}{2}$

Now from the given property,

$m_1\times (-\frac{2}{5})=-1$

$m_1=\frac{5}{2}$

Therefore, slope of altitude BC = $\frac{5}{2}$

Option (C) will be the answer.

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What is the solution set of x^2+y^2=26 and x-y=6?

lubasha [3.4K]

I think it's B because it's makes the most sense

5 0

3 years ago

SO anyways :))))

artcher [175]

Answer:

1 / 8², B

Step-by-step explanation:

8 / 8³

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2 years ago

BD is the angle bisector of

AlexFokin [52]

Note: Let us consider, we need to find the $m\angle ABC$ and $m\angle DBC$ .

Given:

In the given figure, BD is the angle bisector of ABC.

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The $m\angle ABC$ and $m\angle DBC$ .

Solution:

BD is the angle bisector of ABC. So,

$m\angle ABD=m\angle DBC$

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$3x-x=20$

$2x=20$

Divide both sides by 2.

$x=\dfrac{20}{2}$

$x=10$

Now,

$m\angle DBC=(x+20)^\circ$

$m\angle DBC=(10+20)^\circ$

$m\angle DBC=30^\circ$

And,

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2 years ago

mina [271]

Answer:

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Step-by-step explanation:

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3 years ago