All categories

3 years ago

Please answer the question in the picture

Mathematics

1 answer:

Svetlanka [38]3 years ago

3 0

Answer:

Hey kid stop cheating XDDDDDDDDDDDDDDDDDDD

Step-by-step explanation:

You might be interested in

Find the perimeter of the figure.

Alika [10]

1+1=2

2+3=5

5+3=8

8+5=13 inches

3 0

3 years ago

Which statement about this equation is true?

Viktor [21]

The equation has no solution because:

5(n+10)=5n+10n
5n+10n=5n+10n
I subtract 5n from both sides
10n=10n
Only one side is supposed to have the variable which is n, so the equation has no solution.

4 0

3 years ago

Solve for x,<br> m-3x=2x+p

just olya [345]

<span>m-3x=2x+p
m-x=p (- 2x on both sides)
-x=p-m (- m on both sides)
answer: x=-p+m (divide -1 on both side)

</span>

5 0

3 years ago

The temperature at 6 a.M. Was 32 degrees. If the temperatures increased at a constant rate of 3 degrees per hour all day, what w

Stolb23 [73]

It would be 53 degrees i’m pretty sure it’s 53 degrees

4 0

3 years ago

Read 2 more answers

Find the radius of the circle with equation x²+y²+8x+8y+28=0

galina1969 [7]

<h2>Hello!</h2>

The answer is:

Center: (-4,-4)

Radius: 2 units.

To solve the problem, using the given formula of a circle, we need to find its standard equation form which is equal to:

$(x-h)^{2}+(y-k)^{2}=r^{2}$

Where:

"h" and "k" are the coordinates of the center of the circle and "r" is its radius.

So, we need to complete the square for both variable "x" and "y".

The given equation is:

$x^{2}+y^{2}+8x+8y+28=0$

So, solving we have:

$x^{2}+y^{2}+8x+8y=-28$

$(x^2+8x+(\frac{8}{2})^{2})+(y^2+8y+(\frac{8}{2})^{2})=-28+((\frac{8}{2})^{2})++(\frac{8}{2})^{2})\\\\(x^2+8x+16 )+(y^2+8y+16)=-28+16+16\\\\(x^2+4)+(y^2+4)=4$

$(x^2-(-4))+(y^2-(-4))=4$

Now, we have that:

$h=-4\\k=-4\\r=\sqrt{4}=2$

So,

Center: (-4,-4)

Radius: 2 units.

Have a nice day!

Note: I have attached a picture for better understanding.

3 0

3 years ago