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Studentka2010 [4]
3 years ago
15

Ted made a trip to his friends house and back. On the trip there he traveled 25 km/h and on the return trip he went 20 km/h. How

long did the trip there take if the return trip took five hours?
Mathematics
1 answer:
krok68 [10]3 years ago
7 0
Speed = distance/time

distance = speed * time

The return trip took 5 hours, so the time of the return trip is 5 hours.
The speed of the return trip is 20 km/h.

distance = speed * time = 20 km/h * 5 hours = 100 km

The distance is 100 km.
On the way to the friend's house, he traveled at 25 km/h.

time = distance/speed

time = (100 km)/(25 km/h) = 4 hours

It took him 4 hours to get to the friend's house, and it took him 5 hours to get back. The entire trip took 4 hours + 5 hours = 9 hours.
Answer: It took him
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Answer:

97,99,101,103

Step-by-step explanation:

Let x = first odd integer

x+2 = 2nd odd integer

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x+6 = 4th odd integer

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x+ (x+2) + (x+4)+(x+6) = 400

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Divide by 4 on each side

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<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B125%20%7D%20-%20%5Csqrt%7B180%7D%20%2B%20%5Csqrt%7B45%7D%20" id="TexFormula1" tit
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Answer:

2\sqrt{5}

Step-by-step explanation:

Using the rule of radicals

\sqrt{a} × \sqrt{b} ⇔ \sqrt{ab}

Simplifying the radicals

\sqrt{125} = \sqrt{25(5)} = \sqrt{25} × \sqrt{5} = 5\sqrt{5}

\sqrt{180} = \sqrt{36(5)} = \sqrt{36} × \sqrt{5} = 6\sqrt{5}

\sqrt{45} = \sqrt{9(5)} = \sqrt{9} × \sqrt{5} = 3\sqrt{5}

Thus

\sqrt{125} - \sqrt{180} +\sqrt{45}

= 5\sqrt{5} - 6\sqrt{5} + 3\sqrt{5}

= 2\sqrt{5}

3 0
3 years ago
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