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Studentka2010 [4]
3 years ago
15

Ted made a trip to his friends house and back. On the trip there he traveled 25 km/h and on the return trip he went 20 km/h. How

long did the trip there take if the return trip took five hours?
Mathematics
1 answer:
krok68 [10]3 years ago
7 0
Speed = distance/time

distance = speed * time

The return trip took 5 hours, so the time of the return trip is 5 hours.
The speed of the return trip is 20 km/h.

distance = speed * time = 20 km/h * 5 hours = 100 km

The distance is 100 km.
On the way to the friend's house, he traveled at 25 km/h.

time = distance/speed

time = (100 km)/(25 km/h) = 4 hours

It took him 4 hours to get to the friend's house, and it took him 5 hours to get back. The entire trip took 4 hours + 5 hours = 9 hours.
Answer: It took him
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What is the solution to the equation 1/4x+2=-5/8x-5<br> O X=-8<br> O x=-7<br> O X= 7<br> O X=8
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x = -8

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solve this system of linear equations. separate the x- and y- values with a comma. 6x +5y=-19 12x-8y=52
Ymorist [56]

ANSWER

The solution is

(x,y)=(1,-5)

EXPLANATION

The equations are:

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3rd equation: 12x +10y=-38

Subtracy the 2nd equation from the 3rd equations.

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The solution is

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