All categories

2 years ago

Two of the vertices were (4, –3) and (–1, –3).What could be the coordinates of the other two vertices of the rectangle?

Mathematics

1 answer:

aivan3 [116]2 years ago

6 0

-1,3 and 4,3

the “x” stays the same and the “y” is opposite to form a rectangle

You might be interested in

He graph of the function f(x) = –(x + 6)(x + 2) is shown below.

Molodets [167]

The domain of the function is all real numbers, the range of a function is y ≤ 4

<h3>What is a function?</h3>

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

We have a function:

f(x) = –(x + 6)(x + 2)

If we plot this function on the coordinate plane, we will see it is a graph of a quadratic function.

Here the no other details are given.

But we can say:

The domain of the function is all real numbers.
The range of a function is y ≤ 4
The x-axis intercept will be at (-6, 0) and (-2, 0).

Thus, the domain of the function is all real numbers, the range of a function is y ≤ 4

Learn more about the function here:

brainly.com/question/5245372

#SPJ1

6 0

2 years ago

Pls help with this ile give brainlist who ever answers first

katrin [286]

Answer:

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

What are the solutions to the following system?

bija089 [108]

The solutions are $(\sqrt{2},-1) \text { and }(-\sqrt{2},-1)$ .

Solution:

Given equation:

$-2 x^{2}+y=-5$

Add $2 x^{2}$ on both sides.

$-2 x^{2}+y+2 x^{2}=-5+2 x^{2}$

$y=-5+2 x^{2}$ -------- (1)

$y=-3 x^{2}+5$ (given) -------- (2)

Equate (1) and (2).

$-5+2 x^{2}=-3 x^{2}+5$

Add $3 x^{2}$ on both sides.

$-5+2 x^{2}+3 x^{2}=-3 x^{2}+5 +3 x^{2}$

$-5+5x^{2}=5$

Add 5 on both sides.

$-5+5x^{2}+5=5+5$

$5x^{2}=10$

Divide by 5 on both sides, we get

$x^{2}=2$

Taking square root on both sides, we get

$x=\sqrt{2}, x=-\sqrt{2}$

Substitute $x=\sqrt{2}$ in (1).

$y=-5+2(\sqrt{2})^2$

$y=-5+4$

$y=-1$

Substitute $x=-\sqrt{2}$ in (1).

$y=-5+2(-\sqrt{2})^2$

$y=-5+4$

$y=-1$

Therefore the solutions are $(\sqrt{2},-1) \text { and }(-\sqrt{2},-1)$ .

Option C is the correct answer.

6 0

3 years ago

Pls, Help with the discussion essay below.

Rudik [331]

Answer:

I need an image of the question

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Find the area of the circle with the given radius or diameter use pi equals 3.1 4 R is equal to six

marysya [2.9K]

<h2>Hello!</h2>

The answer is:

The area is equal to 113.04 units.

To find the area of the circle, we need to use the given information about the radius (6).

So, the area of a circle is given by the following formula:

$A=\pi *r^{2}$

Where,

$\pi=3.14 (For This Case)\\r=radius$

Substituting the given radius, we have:

$A=3.14*(6)^{2}=3.14*36=113.04units$

Have a nice day!

3 0

3 years ago

Read 2 more answers