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gtnhenbr [62]
3 years ago
13

if a right triangle has one side measuring 4 and another side measuring 6, what is the length of the hypotenuse

Mathematics
2 answers:
Otrada [13]3 years ago
4 0

Answer:

if it helps then plz mark as brainliest

dlinn [17]3 years ago
3 0

Answer:

\sqrt{52}

Step-by-step explanation:

a^{2} + b^{2} =c^{2}

Here, a = 4, and b = 6.  So if you square a, you get 16.  If you square b, you get 36.

16+36 = 52 = c^{2}

Take the square root of 52 and c^{2} and you get that c = \sqrt{52}

This can be simplified further.  c = \sqrt{52} = \sqrt{13*4}  = 2\sqrt{13}

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Is a infinite number that keps going
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Aimees karate class lasts 1hr and 15min and is over at 5:00pm what time does aimees karate class start
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3:45 pm, 1 hour before 5 is 4, and adding 15 minuets makes 3 : 45
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Pamelas age is two times jiris age the sum of their ages is 33 what is jiris age?
Igoryamba

Answer:11 Years Old

Step-by-step explanation:

Well, if you guess and check, if you say jiris’s age is 11, and 11x2 is 22 and 22+11 is 33 and therefore jiris must be 11 years old(pamela is 22 years old)

8 0
3 years ago
The amount of time it takes a bat to eat a frog was recorded for each bat in a random sample of 12 bats. The resulting sample me
spin [16.1K]

Answer: a. CI for the mean: 17.327 < μ < 26.473

b. CI for variance: 29.7532 ≤ \sigma^{2} ≤ 170.9093

Step-by-step explanation:

a. To construct a 95% confidence interval for the mean:

The given data are:

mean = 21.9

s = 7.7

n = 12

df = 12 - 1 = 11

1 - α = 0.05

\frac{\alpha}{2} = 0.025

t-score = t_{0.025,11} = 2.2001

Note: since the sample population is less than 30, it is used a t-score.

The formula for interval:

mean ± t.\frac{s}{\sqrt{n} }

Substituing values:

21.9 ± 2.200.\frac{7.7}{\sqrt{12} }

21.9 ± 4.573

The interval is: 17.327 < μ < 26.473

b. A 95% confidence interval for the variance:

The given values are:

s^{2} = 7.7^{2}

s^{2} = 59.29

α = 0.05

\frac{\alpha}{2} = 0.025

1-\frac{\alpha}{2} = 0.975

\chi^{2}_{0.025,11} = 21.92

\chi^{2}_{0.975,11} = 3.816

Note: To find the values for \chi^{2}_{\alpha/2,n-1} and \chi^{2}_{1-\alpha/2,n-1}, look for them at the chi-square table

The formula to calculate interval:

(\frac{(n-1).s^{2}}{\chi^{2}_{\alpha/2,n-1}} , \frac{(n-1)s^{2}}{\chi^{2}_{1-\alpha/2,n-1}})

are the lower and upper limits, respectively.

Substituing values:

(\frac{11.59.29}{21.92} , \frac{11.59.29}{3.816})

(29.7532, 170.9093)

The interval for variance is: 29.7532 ≤ \sigma^{2} ≤ 170.9093

6 0
3 years ago
The length to nearest fourth inch
atroni [7]

Answer:

3 1/2 inches

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