Answer: Our required probability is 0.83.
Step-by-step explanation:
Since we have given that
Number of dices = 2
Number of fair dice = 1
Probability of getting a fair dice P(E₁) = 
Number of unfair dice = 1
Probability of getting a unfair dice P(E₂) = 
Probability of getting a 3 for the fair dice P(A|E₁)= 
Probability of getting a 3 for the unfair dice P(A|E₂) = 
So, we need to find the probability that the die he rolled is fair given that the outcome is 3.
So, we will use "Bayes theorem":

Hence, our required probability is 0.83.
S2= 864/6
s = = 12 cm
p = 4/3 x 12 = 16 cm
t = 2/4 x 16 = 8 cm
l= 3/4x 16 = 12 cm
lp= 2 (pl+pt+lt)
= 2 (16 x 12 + 16 x 8 + 12 x8)
= 2 (192+128+96) = 832cm²
Answer: x = 5
Step-by-step explanation:
Want me to show this, or did you just want the answer?
12 because if you take 2 and add it to 10 you get 12
+
there u go if that helps u can copy and paste it