They are about 27 percent that are not seniors
(-8)/(2y-8)=(5/(y+4))-7y+(8/(y^2-16))
(-4)/(y-4)=(5/(y+4))-7y+(8/(y+4)(y-4))
((-4)(y+4))/((y+4)(y-4))=((5(y-4))/(y+4)(y-4))-(7y(y+4)(y-4))/(y+4)(y-4))+(8/(y+4)(y-4))
(-4(y+4))=(5(y-4))-(7y(y+4)(y-4))+8
-4y-16=5y-20-(7y(y^2-16))+8
-4y-16=5y-20-7y^3+112y+8
-4y-16=117y-7y^3-12
-4=(121-7y^2)(y)
None of these choices would be equal to -4
Answer:
v = -3
Step-by-step explanation:
1) Expand.
3v + 4v - 8 = -29
2) Simplify 3v + 4v - 8 to 7v - 8.
7v - 8 = -29
3) Add 8 to both sides.
7v = -29 + 8
4) Simplify -29 + 8 to -21.
7v = -21
5) Divide both sides by 7.
v = -21/7
6) Simplify 21/7 to 3.
v = -3
Answer: Choice C) AA similarity
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We are given that angle ABE = angle ECD since they are both right angles (square marker)
Angle AEB = angle CED as they are vertical angles
we have two pairs of congruent angles, leading us to be able to use the AA (angle angle) similarity theorem
16.5 degrees below the starting temp, whatever that is. If its 0, then -16.5 degrees.
The first equation would be (.5)5-11=-8.5, because the metal has been cooling for 5 hours.
The device that 'aids' in the cooling would be -5-3=-8, because it is a separate variable that cools the metal, so the amount the device cools is independent of the natural cooling amount, and the equation is independent of the natural cooling equation.
You then add -8.5 and -8, because the device has lowered 8.5 degrees and 8 degrees. This equals -16.5 degrees, or a decrease of 16.5 degrees.
