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Len [333]
2 years ago
15

an airplane flies in the path shown by the vector line UV on the graph below. what is the magnitude and direction of line UV? (1

unit represents 1 mile)

Mathematics
1 answer:
GaryK [48]2 years ago
4 0

The magnitude and direction of line UV is 19.7° South of West for 8.1 miles

<h3>How to find the magnitude of the vector line UV?</h3>

The magnitude of the vector line UV is given by the length of the line UV,

d = √[(x₂ - x₁)² + (y₂ - y₁)²] where

  • (x₁, y₁) = (2, 3) and
  • (x₂, y₂) = (-2, -4)

Substituting the values of the variables intot he equation, we have

d = √[(x₂ - x₁)² + (y₂ - y₁)²]

d = √[(-2 - 2)² + (-4 - 3)²]

d = √[(-4)² + (-7)²]

d = √[4² + 7²]

d = √[16 + 49]

d = √65

d = 8.06 miles

d ≅ 8.1 miles

So, the magnitude of vector line UV is 8.1 miles

<h3>How to find the direction of the vector line UV</h3>

The direction of the vector line UV is given by Ф = tan⁻¹[(y₂ - y₁)/(x₂ - x₁)] where

  • (x₁, y₁) = (2, 3) and
  • (x₂, y₂) = (-2, -4)

Substituting the values of the variables into the equation, we have

Ф = tan⁻¹[(y₂ - y₁)/(x₂ - x₁)]

Ф = tan⁻¹[(-4 - 3)/(-2 - 2)]

Ф = tan⁻¹[(-7)/(-4)]

Ф = tan⁻¹[7/4]

Ф = tan⁻¹[1.75]

Ф = 60.26°

Ф ≅ 60.3°

Its bearing from the north-south line is α = 90° - Ф

= 90° - 60.3°

= 19.7°

So, its direction is 19.7° South of West

So, the magnitude and direction of line UV is 19.7° South of West for 8.1 miles

Learn more about vectors here:

brainly.com/question/26700114

#SPJ1

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